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stellarik [79]
3 years ago
8

An object acted on by three forces moves with constant velocity. one force acting on the object is in the positive x direction a

nd has a magnitude of 6.3 n; a second force has a magnitude of 4.3 n and points in the negative y direction. find the direction and magnitude of the third force acting on the object.
Physics
1 answer:
Afina-wow [57]3 years ago
4 0
10.6 is the answer i think im not the best at math
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Consider the numbers 23.68 and 4.12. The sum of these numbers has ____ significant figures, and the product of these numbers has
damaskus [11]

Answer:multiplying will give us 7 significant figures and addition will give us 3 significant figures

Explanation:

After multiplying the two numbers they resulting value will give a value in its 4 decimal places because both given values are in 2 decimal places. The 4 dp is gotten by the addition of the decimal places of both given numbers (2+2) and

The result of its addition will give us a value in its 1dp and 3 significant figures since the addition of 23.68 and 4.12 will give us 27.8

7 0
3 years ago
A rock of mass m is thrown straight up into the air with initial speed |v0 | and initial position y = 0 and it rises up to a max
REY [17]

Answer:

Explanation:

Case 1:

mass = m

initial velocity = vo

final velocity = 0

height = y

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v² = u² - 2as

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Case 2:

mass = 2m

initial velocity = 2vo

final velocity = 0

height = y '

Use third equation of motion

v² = u² - 2as

0 = 4vo² - 2 g y'

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Thus, the second rock reaches the 4 times the distance traveled by the first rock.

7 0
3 years ago
If a builder of mass 75kg climbs a vertical ladder of 25m how much energy has she gained ?
erica [24]
So,

GPE (graviational potential energy) = mass x g x height

GPE is depends on where zero height is defined.  In this situation, we define h = 0 as the initial height.

GPE = 75 \ kg*9.8 \ \frac{m}{s^2}*25 \ m

GPE = 18,375 \frac{kg*m^2}{s^2}

GPE = 18,375 \ joules(J) \ or \ 18.375 \ kilojoules(kJ)

The builder has gained 18.375 kJ of PE.
4 0
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timama [110]

When an unbalanced force acts on an object the change in the object state of rest or motion depends on the size and direction of the force.

If a body is at state of rest or motion, when an unbalanced external force acts on it, its starts moving in the direction of force and magnitude of its velocity or acceleration depends on the magnitude of force applied.

7 0
3 years ago
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