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Veronika [31]
3 years ago
13

When does the fall equinox occur in the northern hemisphere

Physics
1 answer:
aivan3 [116]3 years ago
7 0

Here is your answer

On 23rd September

HOPE IT IS USEFUL

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Which equation below would you use to determine the number of neutrons in a given nucleus when you are given the atomic number (
Mademuasel [1]

Answer:

A-Z

Explanation:

A proton has an estimated weight of 1.

6 0
4 years ago
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Our solar system formed from a huge cloud of dust and gas called a _____.
Mumz [18]
Our solar system formed from a huge cloud of dust and gas called a
c. solar nebula

Based on the nebular hypothesis, our solar system formed from hydrogen gas and interstellar dust. The gas and the dust contracted and formed the early stage of the sun.
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3 years ago
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A football player, with a mass of 69.0 kg, slides on the ground after being knocked down. At the start of the slide, the player
White raven [17]

Answer:

(a) -472.305  J

(b) 1 m

Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by0.5mv^{2}

Initial kinetic energy is 0.5\times 69\times 3.7^{2}=472.305 J

Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305  J=-472.305  J

(b)

From fundamental kinematic equation

v^{2}=u^{2}+2as

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

s=\frac {v^{2}-u^{2}}{-2a} but a=\mu g hence

s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m

7 0
3 years ago
An iron nail is made up of particles. What is true about the particles?
sesenic [268]
The particles are very compact and dense in the iron nail.
3 0
4 years ago
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Two spheres having masses M and 2M and radii R and 3R, respectively, are released from rest when the distance between their cent
Andrei [34K]

Answer:

v_2 = \sqrt{\frac{GM}{3R}}

v_1 = 2\sqrt{\frac{GM}{3R}}

Explanation:

As we know by energy conservation that change in gravitational potential energy of the system = change in kinetic energy of the two ball

So here we can say

-\frac{GM(2M)}{12R} + 0 = -\frac{GM(2M)}{4R} + \frac{1}{2}Mv_1^2 + \frac{1}{2}(2M)v_2^2

Also since there is no external force on the system of two masses so here total momentum of the two balls will remains conserved

0 = Mv_1 + 2Mv_2

v_1 = -2v_2

now we have

\frac{GM^2}{2R} - \frac{GM^2}{6R} = \frac{1}{2}M(-2v_2)^2 + \frac{1}{2}(2M)v_2^2

\frac{GM^2}{3R} = Mv_2^2

v_2 = \sqrt{\frac{GM}{3R}}

v_1 = 2\sqrt{\frac{GM}{3R}}

4 0
4 years ago
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