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Vilka [71]
3 years ago
14

An element X exists as three naturally occurring isotopes. If all isotopes have the same atomic number, what would be the differ

ence in the three isotopes?
Chemistry
1 answer:
inn [45]3 years ago
7 0

Answer:

the amount of neutrons would be the difference in the three isotopes

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1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate
Whitepunk [10]

a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g

6 0
3 years ago
Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh
kozerog [31]
The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

calculate the moles  of CaCO3  used

that is  moles =mass/molar mass
convert  Kg  to g  = 4.510 x1000 =4510g
=  4510 / 100 =45.10 moles
CaCO3 = CaO  +O2

by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
mass of CaO = moles x molar  mass

45.10  x56 = 2525.6  g  of  CaO



6 0
3 years ago
Read 2 more answers
How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g
SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = \frac{Lead}{Water} \times 10^6 = \frac{1.30}{250} \times 10^6 = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0
3 years ago
PLEASE HELP!!!!!
Free_Kalibri [48]
Umm I think it might be a b c in order?
4 0
3 years ago
How many atoms are in<br> 3Ca(CIO3)2
satela [25.4K]

Answer:

Explanation:

Percent composition by element

Element Symbol # of Atoms

Chlorine Cl 2

Calcium Ca 1

Oxygen O 6

4 0
2 years ago
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