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Korvikt [17]
3 years ago
13

How do the water molecules on a

Chemistry
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

It frezzes over

Explanation:

because it goes across the whole lake and it puts bacteria in it

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Why the moon is the barycenter of earth?
baherus [9]
Because it wanted to be
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3 years ago
Which of the following is not a reason why actual yield is less than theoretical yield?
Gnom [1K]
Your answer is B, conservation of mass


Recall that percent yield is given by: %Yeild = actual yeild/theoretical yeild x100

During experiments, there are errors made:

• uncertainty in measurements

• losses of reactants and products

• impurity in reactants

• losses during separation (e.g. filtration or purification)

• Some side reactions might also happen.



Among the given options, only conservation of mass does not contribute to a lower actual yield compared to the theoretical yield.

5 0
3 years ago
If a solution has virtually no hydrogen ions what type of ph does it have?
lora16 [44]
D. It has almost no hydrogen ions, therefore it is very basic.
7 0
3 years ago
Read 2 more answers
If 0.0692 mol CaCl2 is dissolved in water to make a 0.810 M solution, what is the volume of the solution?
Natali5045456 [20]

Answer:

Just ask google for help

Explanation:

I always do it and get it right

8 0
3 years ago
A compound with molecular formula C5H10O2 has the following 1H NMR spectrum: 1.15 (t, 3H), 1.25 (t, 3H), 2.33 (q, 2H), 4.13 (q,
Vilka [71]

Answer:

Ethyl propionate

Explanation:

Calculating the double bond equivalence as:

DBE =  C - (H/2) - (X/2) + (N/2) +1

Where  

C is the number of carbon atoms

N is the number of nitrogen atoms

X is the number of halogens

H is the number of hydrogen atoms

So, according to the formula, C_5H_{10}O_2

DBE =  5 - (10/2) - (0/2) + (0/2) +1 = 1

It means there is one double bond or one ring.

from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.

From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.

The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have

-OCH_2CH_3.

Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.

So the compound is ethyl propionate

3 0
3 years ago
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