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3 years ago

Find the length of the indicated side of the similar figure

Mathematics

1 answer:

neonofarm [45]3 years ago

7 0

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Please help me!!!!!!!

noname [10]

Answer:

D) 5 miles to 1 hour.

Step-by-step explanation:

If each small box is 1 mile you can count the boxes to line up with the 1 hour graph. Hence, 5 boxes to 1 hour box equals 5 miles to the hour.

7 0

3 years ago

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Igoryamba

Answer: 2.43m^3

Step-by-step explanation:

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3 years ago

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A water tower casts a 100- foot shadow. At the same time, an 8- foot street sign casts a shadow of 6 feet. what is the height of

Elina [12.6K]

Set up and solve an equation of ratios. Comparing shadow lengths, we get 100/6; comparing heights, we get x/8. Set these two ratios equal to one another and solve the resulting equation for x:

100 x
----- = ------ Then 6x=800, and x = 800 feet^2 over 6 feet. Your answer
6 8

must have the unit of measurement "ft."

6 0

3 years ago

Find the area of the trapezoid.

goldenfox [79]

Answer:

Step-by-step explanation:

AREA=

$\frac{(a + b)}{2} \times h$

$\frac{15 + 6}{2} \times 10$

=105m²

6 0

3 years ago

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

− 10x²y = 2 $*$ - 5 $*$ x² $*$ y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,

$\left(x^3-5x^2\right)+\left(9x-45\right)$ - Factor 9 from 9x - 45 and x² from x³ - 5x²,

$9\left(x-5\right)+x^2\left(x-5\right)$ - Factor out common term x - 5,

$\left(x-5\right)\left(x^2+9\right)$ - And our solution is thus 2y( x - 5 )( x² + 9 )

3 0

3 years ago