The inside of a beaker is shaped like a circular cylinder with a base diameter of 121212 centimeters (\text{cm})(cm)(, start tex
t, c, m, end text, ). Water in the beaker is filled to a height of 8\,\text{cm}8cm8, start text, c, m, end text above the base. A stainless steel sphere with a diameter of 6\,\text{cm}6cm6, start text, c, m, end text submerged in the liquid displaces an equal volume of water. How high above the base of the beaker is the new water level, in centimeters
Since the container is a cylinder of base diameter d₁ = 12 cm and thus radius r = 12/2 = 6 cm. The water height is 8 cm. The initial volume of water is thus V₁ = πr²h = π × 6² × 8 = 288π cm³.
The sphere of diameter d = 6 cm has radius r₁ = 6/2 = 3 cm. Its volume V₂ = 4πr³/3 = 4π × 3³/3 = 36π cm³
Since the sphere displaces it own volume of liquid, the new volume V = V₁ + V₂ = 288π cm³ + 36π cm³ = 324π cm³
This is the new volume of water in the cylinder. Since the water level rises by h' cm and V = πr²h'
Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below
Hence, in our case
Transform points N, M, and O accordingly,
<h2>Therefore, the answer is the first option (top to bottom)</h2>
