Answer:
Any number smaller than 2
Step-by-step explanation:
You would graph this by wrighting a solid, filled in circle with an arrow point toward the negative numbers, because those numbers are smaller than 2
4x=-7 is the answer because "the number" should be the variable
Answer:
At least 37.74% of the procedures takes between 97.6 and 125.6 minutes
Step-by-step explanation:
The percentage is the area of the standard normal distribution curve between the values 97.6 and 125.6
The standard normal variate of the given data is found as
Thus for the given values Z is calculated as under
Similarly for the other value we have
Thus the area between the calculated values can be found from standard normal distribution table to be 37.74%
Answer:
After reflection over the x-axis, we have the coordinates as follows;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Step-by-step explanation:
Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis
By reflecting over the x-axis, the y-coordinate is bound to change in sign
So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)
We simply go on to negate the value of the y-coordinate
Mathematically if we apply these to the given points, what we get are the following;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
For the answer to the question above,
The mean value theorem states the if f is a continuous function on an interval [a,b], then there is a c in [a,b] such that:
<span>f ' (c) = [f(b) - f(a)] / (b - a) </span>
<span>
So [f(a) - f(b)] ( b - a ) = [sin(3pi/4) - sin(pi/4)]/pi </span>
= [sqrt(2)/2 - sqrt(2)/2]/pi = 0
So for some c in [pi/2, 3pi/2] we must have f ' (c) = 0
In general f ' (x) = (1/2) cos (x/2)
We ask ourselves for what values x in [pi/2, 3pi/2] does the above equation equal 0.
0 = (1/2) cos (x/2)
0 = cos (x/2)
x/2 = ..., -5pi/2, -3pi/2, -pi/2, pi/2, 3pi/2, 5pi/2,...
x = ..., -5pi, -3pi, -pi, pi. 3pi, 5pi, ....
and x = pi is the only solution in our interval.
So c = pi is a solution that satisfies the conclusion of the MVT
