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kari74 [83]
3 years ago
9

How many cells are needed to create a living organism?

Chemistry
1 answer:
snow_lady [41]3 years ago
4 0
The average human has between sixty trillion and ninety trillion cells, but there are also organisms that have only a single cell. So basically it depends on the type of organism, but the minimum amount of cells is one.
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Balance the following equation<br><br> CH₄ + O₂ → CO₂ + H₂O
nalin [4]

Answer:

CH4 + 2 O2 - - - > CO2 + 2 H2O

Explanation:

hope this helps,

you can check by adding all the numbers on both sides

please mark it

3 0
3 years ago
A phosphate buffer solution (25.00 mL sample) used for a growth medium was titrated with 0.1000 M hydrochloric acid. The compone
AysviL [449]

Answer:

0,07448M of phosphate buffer

Explanation:

sodium monohydrogenphosphate (Na₂HP) and sodium dihydrogenphosphate (NaH₂P) react with HCl thus:

Na₂HP + HCl ⇄ NaH₂P + NaCl <em>(1)</em>

NaH₂P + HCl ⇄ H₃P + NaCl <em>(2)</em>

The first endpoint is due the reaction (1), When all phosphate buffer is as NaH₂P form, begins the second reaction. That means that the second endpoint is due the total concentration of phosphate that is obtained thus:

0,01862L of HCl×\frac{0,1000mol}{L}= 1,862x10⁻³moles of HCl ≡ moles of phosphate buffer.

The concentration is:

\frac{1,862x10^{-3}moles}{0,02500L} = <em>0,07448M of phosphate buffer</em>

<em></em>

I hope it helps!

7 0
3 years ago
What is the molality of a solution prepared by dissolving 150.0 g C6H12O6 in 600.0 g of H2O?
elena-14-01-66 [18.8K]

Answer:

50/36 = 25/18

Explanation:

Solution at attachment box

Molality = mole of dissolvable (this question glucose) / kg of water

4 0
3 years ago
Read 2 more answers
Explain why the quantum number set (3, 3, -2, +½) is not possible for an electron in a ground-state atom.
Solnce55 [7]

Answer:- It's not correct because the values of n and l are same.

Explanations:- The four quantum numbers are n, l, ml and ms where n stands for Principal quantum number and has values like 1, 2, 3 and so on.

l stands for azimuthal quantum number and has values from 0 to (n-1) where n is principal quantum number.

For the given set of quantum numbers, value of n is 3. So, the possible values of l would be 0,1 and 2.

The value of l for the given set of quantum numbers is 3 which is the reason why the given set is not possible.

5 0
3 years ago
Supplementary<br> vertical<br> complementary<br> similar
Leya [2.2K]
Vertical angles should be your answer

hope this helps
8 0
3 years ago
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