Question

When 2 moles of K3PO4 is dissolved in water, how many moles of ions are produced? For your answer do not put units, just the numeric value.

Answer 1

Hey there!

1 mole of K3PO4 (aq)  gives 3 moles of K⁺ ions , and 1 mole  of PO₄³⁻ ion

So:

K3PO4(aq) ⇌ 3 K⁺(aq) + PO₄³⁻(aq)

There are 4 moles of ions , when 2 moles of K3PO4(aq) is dissolved in water.

6 moles of K⁺  + 2 moles of PO₄³⁻ ions are formed !

There  are total 8 moles of ions .

Hope that helps!

Answer 2

Answer: 8 moles of ions are produced when $K_3PO_4$ is dissolved in water.

Explanation: When $K_3PO_4$ is dissolved in water, ionization reaction takes place. The reaction follows:

$K_3PO_4(aq.)\rightarrow 3K^+(aq.)+PO_4^{3-}(aq.)$

By stoichiometry,

1 mole of $K_3PO_4$ produces 3 moles of $K^+$ and 1 mole of $PO_4^{3-}$

So, 2 moles of $K_3PO_4$ will produce (2 ×3) = 6 moles of $K^+$ and (2 × 1) = 2 moles of $PO_4^{3-}$

Hence, total moles of ions produced = ( 6 + 2 ) = 8 moles of ions.