Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
V1/T1=V2/T2
(10)/(358K)=(V2)/(278)
V2=7.765363128 L
.....to obey the law of conservation of mass.
Explanation:
Metals are the species which readily lose electrons in order to attain stability. This electron lost by the atom is actually present in its outermost shell which is also known as valence shell.
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.
But when we move down a group then there occurs an increase in atomic size of the atoms due to addition of number of electrons in the atoms. Hence, ionization energy decreases along a group.
Thus, we can conclude that metals have low ionization energies and readily share their valence or outer electrons with each other to form an electron sea. These electrons are delocalized or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.
Answer:
Phosphorus
Explanation:
In given diagram there are 15 electrons are present. Which means it is orbital diagram of phosphorus.
The atomic number of phosphorus = 15
Number of electrons = 15
Electronic configuration of phosphorus:
P₁₅ = 1s² 2s² 2p⁶ 3s² 3p³
All other options are incorrect because:
Calcium have 20 electrons.
Electronic configuration of Ca:
Ca₂₀ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Hydrogen have one electron.
Electronic configuration of H.
H₁ = 1s¹
Magnesium have 12 electrons:
Electronic configuration of Mg:
Mg₁₂ = 1s² 2s² 2p⁶ 3s²