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Sonja [21]
3 years ago
13

A 0.142 kg remote control 24.0 cm long rests on a table, as shown in the figure(Figure 1) , with a length L overhanging its edge

. To operate the power button on this remote requires a force of 0.355 N .
How far can the remote control extend beyond the edge of the table and still not tip over when you press the power button? Assume the mass of the remote is distributed uniformly, and that the power button is 1.51 cm from the overhanging end of the remote.
Physics
1 answer:
mamaluj [8]3 years ago
5 0
Long as question ....
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Two protons, starting several meters apart, are aimed directly at each other with speeds of 2.00 * 105 m>s, measured relative
victus00 [196]

Explanation:

Since, the two protons are at the initial state of point a and point b. Hence, total mechanical energy at point a and point b is as follows.

           U_{a} + K_{a} = U_{b} + K_{b}

or,           K_{a} = U_{b}  

where,   K_{a} = kinetic energy of two protons

So,      2(\frac{1}{2}mV^{2}_{a}) = \frac{1}{4 \pi \epsilon_{o}} \frac{|e|^{2}}{r_{b}}

       r_{b} = \frac{1}{4 \pi \epsilon_{o}} \frac{e^{2}}{mV^{2}_{a}}

Putting the given values into the above formula we will calculate the value of r_{b} as follows.

      r_{b} = \frac{1}{4 \pi \epsilon_{o}} \frac{e^{2}}{mV^{2}_{a}}

                = (9.0 \times 10^{9} Nm^{2}/C^{2} \frac{(1.602 \times 10^{-19}^{2} C}{1.67 \times 10^{-27} kg \times 2 \times 10^{5}}

                = 3.45 \times 10^{-12} m

Now, we will calculate the maximum electric field as follows.

      F = \frac{1}{4 \pi \epsilon_{o}} \frac{|e|^{2}}{r^{2}_{b}}

         = 9.0 \times 10^{9} Nm^{2}/C^{2} \frac{(1.602 \times 10^{-19}C)^{2}}{3.45 \times 10^{-12}}

         = 0.194 \times 10^{-4} N

Therefore, we can conclude that the maximum electric force that these protons will exert on each other is 0.194 \times 10^{-4} N.

7 0
3 years ago
A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 n at an angle of 32.0° ab
Phoenix [80]
According to Newton's second law, the resultant of the forces acting on the box is equal to the product between its mass and its acceleration:
\sum F = ma (1)

we are only concerned about the horizontal direction, so there are only two forces acting on the box in this direction:
- the horizontal component of the force exerted by the rope, which is equal to
F_x = F cos \theta = (250N)(\cos 32.0^{\circ} )=212.0 N
- the frictional force, acting in the opposite direction, which is equal to
F_f = \mu mg=(0.350)(50.0 kg)(9.81 m/s^2)=171.7 N

By applying Newton's law (1), we can calculate the acceleration of the box:
F_x - F_f = ma
a= \frac{F_x - F_f}{m}= \frac{212.0 N-171.7 N}{50.0 kg} =0.81 m/s^2

6 0
4 years ago
An astronaut drops a rock on the surface of an asteroid.The rock is released from rest at a height of 0.86 m above the ground, a
SCORPION-xisa [38]

Answer:

a_y=0.92m/s^2

Explanation:

To solve this problem we use the formula for accelerated motion:

y=y_0+v_{y0}t+\frac{a_yt^2}{2}

We will take the initial position as our reference (y_0=0m) and the downward direction as positive. Since the rock departs from rest we have:

y=\frac{a_yt^2}{2}

Which means our acceleration would be:

a_y=\frac{2y}{t^2}

Using our values:

a_y=\frac{2(0.86m)}{(1.37s)^2}=0.92m/s^2

5 0
3 years ago
iron β is a solid phase of iron still unknown to science. The only difference between it and ordinary iron is that Iron β forms
saw5 [17]

Answer:

8.60 g/cm³

Explanation:

In the lattice structure of iron, there are two atoms per unit cell. So:

\frac{2}{a^{3} }  = \frac{N_{A} }{V_{molar} } where V_{molar}  = \frac{A}{\rho } an and A is the atomic mass of iron.

Therefore:

\frac{2}{a^{3} } = \frac{N_{A} * p }{A}

This implies that:

A = (\frac{2A}{N_{A} * p)^{\frac{1}{3} }  }

  = \frac{4}{\sqrt{3} }r

Assuming that there is no phase change gives:

\rho = \frac{4A}{N_{A}(2\sqrt{2r})^{3}   }

  = 8.60 g/m³

3 0
4 years ago
QUICCCKKKKK!!!!!!!!!!Stimulus discrimination occurs when an organism generalizes one consequence to many stimuli similar to the
timama [110]
False i just took the test and put true as a guess but got it wrong so it is false

please give me a brainlies
7 0
3 years ago
Read 2 more answers
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