How do I find the resultant force of a skydiver falling with gravity constant of 10 newtons and his weight is 70 kg??
1 answer:
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The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:
Where,
Final and initial velocity
a = Acceleration
x = Displacement
For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore
Our values are given as
Replacing we have that,
Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s
Answer:
(A⃗ ×B⃗ )⋅C⃗ = 69.868
Explanation:
We simplify the cross product first, thereafter the solution of the cross product is now simplified with the dot product as shown in the step by step calculation in the attachment
