the electric current in a wire is 1.5 A. How many electrons flow past a given point in a time of 2 s?
1 answer:
Answer:
The quantity of electrons that flows past a given point is 3.0 C.
Explanation:
An electric current (I) is the ratio of the quantity of charges (Q) that flows through a point to the time taken (t).
i.e I =
It is measured in Ampere's by the use of an ammeter in the laboratory. The quantity of charge that flow through a given point is measured in Coulombs, while time is measured in seconds.
Given that; I = 1.5A and t = 2s, find Q.
Q = It
= 1.5 × 2
= 3.0 C
The quantity of electrons that flows past a given point is 3.0 C.
You might be interested in
The initial velocity of the potato is 54.41 m/s.
The given parameters:
- <em>Mass of the potato, m = 0.34 kg</em>
- <em>Mass of the cart, m = 5.0 kg </em>
- <em>Velocity of the recoil, u₂ = 3.7 m/s</em>
<em />
The initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;
Thus, the initial velocity of the potato is 54.41 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
a) Please find attached the diagram of the fundamental or first harmonics of tube the created with Microsoft Word
b) The fundamental frequency consists of half wavelength
c) The frequency of the fundamental is 69 Hz
d) The frequency of the third harmonic is 207 Hz
Explanation:
The given parameters of the tube are;
The length of the tube, L = 2.5 m
The speed of sound, c = 345 m/s
a) Please find the diagram of the first harmonics created with Microsoft Word
b) The wavelength of the fundamental frequency, λ₁ = 2·L
Therefore, λ₁ = 2 × 2.5 m = 5.0 m
Therefore, the fundamental frequency consists of 1/2 wavelength
c) The frequency = (The speed of the wave)/(The wavelength of the wave)
The frequency of the fundamental frequency, f₁ = 345 m/s/(5.0 m) = 69 Hz
f₁ = 69 Hz
d) The frequency of the third harmonic, f₃ = 3 × f₁
∴ f₃ = 3 × 69 Hz = 207 Hz
The frequency of the third harmonic, f₃ = 207 Hz
