the normal force is the force applied opposite to the weight
of the was box. So the normal force is equal to the weight of the box = 24 kg
*(9.81 m/s2) = 235.44 N
the acceleration of the box be solve using newtons 2nd
law of motion:
F = ma
a = F/ m = 585 N/ 24 kg = 24.38 m/s2
Answer:
5.2791264*10¹³
Explanation:
Convert the 9 years to seconds and then multiple it by 186000
Answer:
Explanation:
mass of the ball = 146 g = 146 / 1000 = 0.146 kg
initial speed of the ball = 40.6 m/s
final speed of the ball = - 45.1 m/s
time of impact = 1.05 ms = 1.05 / 1000 = 0.00105 s
impulse, Ft = change in momentum = mv - mu = m (v-u)
F = m (v - u) / t = 0.146 kg ( -45.1 -40.6) / 0.00105 s = -11916.4 N
Answer:
The friction coefficient's minimum value will be "0.173".
Explanation:
The given query seems to be incomplete. Below is the attached file of the complete question.
According to the question,
(a)
The net friction force's magnitude will be:
⇒ 


(b)
For m₃,
⇒ 
Or,
⇒ 

