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3 years ago

Question 4 need this answered asap (chemistry)

Chemistry

1 answer:

aleksandrvk [35]3 years ago

3 0

Answer:

Conductivity meter

Explanation:

All of the other choices measure pH and can tell you when the pH changes, which is how you know the neutralization reaction has occurred. A conductivity meter does not measure pH.

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Write down the names, physical properties, and inertness of NOBLE GASES ( group no. 8)

o-na [289]

Answer:

There's No Answer Im Sorry

4 0

3 years ago

A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). What is the emf of this cell under st

Leviafan [203]

Answer:

0.46 V

Explanation:

The emf for the cell is given by:

Eº cell = Eº oxidation + Eº reduction

From the given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced from 0 to negative 2, according to the half cell reactions:

4Fe²⁺ ⇒ Fe³⁺ + 4e⁻ oxidation

O₂ + 4H⁺ + 4 e⁻ ⇒ 2 H₂O reduction

From reference tables for the standard reduction potential, we get

Eº red Fe³⁺ / Fe²⁺ Eºred = 0.77 V

Eº red O₂ / H₂O Eºred = 1.23 V

Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction O₂:

Eº cell = Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V

5 0

3 years ago

This volcanic rock formed _____ from lava _____ in gas.

Evgen [1.6K]

C or a one of those hope it helps !!!!

7 0

3 years ago

Read 2 more answers

A CaCl2 solution is given to increase blood levels of calcium. If a patient receives 6.1 mL of a 12 % (m/v) CaCl2 solution, how

Yuliya22 [10]

Mass of CaCl₂ = 0.732 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

$\tt \%(m/v)\rightarrow 12\%=\dfrac{mass~CaCl_2}{volume~of~solution}\times 100\%\\\\mass~CaCl_2=12\%\times 6.1\div 100\%\\\\mass~CaCl_2=0.732~g$

5 0

3 years ago

Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).

babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0

3 years ago