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Simora [160]
3 years ago
13

Use the balanced equation below to answer the question that follows

Chemistry
1 answer:
Shkiper50 [21]3 years ago
6 0
The answer will be C
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Which situation would lead to increased competition
I am Lyosha [343]

I would say B because c and d would decrease competition and a would do the same, or just kill the ecosystem.

Hope this helps and don't forget to hit that heart :)

8 0
3 years ago
A student places an object on a balance. Which measurement might the student record based on the balance reading? A. 2.4 kilogra
gtnhenbr [62]
A would be the correct answer
8 0
1 year ago
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
The frequency of an x-ray wave is 3.0 x 1012MHz. Its wave speed is 3.0x 108m/s. Calculate the wavelength of the x-ray wave below
jasenka [17]

Answer: The wavelength of the x-ray wave is 10^{-10}m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light  = ?

c = speed of x-ray= 3.0\times 10^8m/s

\nu = frequency of x-ray = 3.0\times 10^{12}MHz=3.0\times 10^{18}Hz= 3.0\times 10^{18}s^{-1}     (1Hz=1s^{-1})

Putting in the values:

\lambda=\frac{3.0\times 10^8m/s}{3.0\times 10^{18}s^{-1}}=10^{-10}m

Thus the wavelength of the x-ray wave is 10^{-10}m

5 0
3 years ago
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