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antoniya [11.8K]
1 year ago
8

Write a reaction and balance it for the reaction of lead with hydrochloric acid

Chemistry
1 answer:
LenKa [72]1 year ago
8 0

A balanced the reaction of lead with hydrochloric acid:

Pb(aq) + 2HLC (l) → PbCl2(aq) + H2(g)

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(WILL GIVE BRAINLESS )Complete the sentence describing Newton's third law of motion: For every action in one direction, O b ос O
Liono4ka [1.6K]

Answer:

An equal force acts in the opposite direction.

Explanation:

3 0
3 years ago
Brownian motion is not observed in a mixture that includes two phases. Which best identifies the mixture? [A} a colloid
Hoochie [10]

b, a suspension

Hope this helped :)

3 0
3 years ago
Which of the following molecules experience dipole-dipole forces as its strongest IMF? A) H2 B) SO2 C) NH3 D) CF4 E) BCl3
Xelga [282]

Answer: NH_3

Explanation:

a) H_2: This  is a non polar covalent compound which are held by weak vanderwaal forces of attraction.

b) SO_2: This  is a covalent compound which is polar due to the presence of lone pair of electrons and are held by dipole-dipole forces of attraction.

c) NH_3: These are joined by a special type of dipole dipole attraction called as hydrogen bond. It forms between electronegative nitrogen atom and hydrogen atom and is the strongest interaction.

d) CF_4: This  is a covalent compound and is non polar which are held by weak vanderwaal forces of attraction.

e)  BCl_3: This  is a covalent compound and is non polar which are held by weak vander waal forces of attraction.

5 0
3 years ago
Select the correct answer.
kirza4 [7]

Answer: A. It indicates the direction in which the reaction occurs.

4 0
1 year ago
How many moles of compound are there in the following?
slavikrds [6]

a) (NH4)2SO4 --- 1 mole of it contains 2 moles of N, 8 moles of H, 1 mole of S, and 4 moles of O.

MM = (2 moles N x 14.0 g/mole) + (8 moles H x 1.01 g/mole) + (1 mole S x 32.1 g/mole) + (4 moles O x 16.0 g/mole) = 132 g/mole.

6.60 g (NH4)2SO4 x (1 mole (NH4)2SO4 / 132 g (NH4)2SO4) = 0.0500 moles (NH4)2SO4

b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.

4.5 kg Ca(OH)2 x (1000 g / 1 kg) x (1 mole Ca(OH)2 / 74.0 g Ca(OH)2) = 60.8 moles Ca(OH)2

8 0
3 years ago
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