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Natalka [10]
3 years ago
13

Which of the following forms of electromagnetic radiation are considered non-ionizing? Select all that apply.

Physics
1 answer:
vazorg [7]3 years ago
4 0
Visible light and radio waves.
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What is the natural frequency (wo) of a circuit that has an inductor of 0.048 henery's, and a capacitor of 0.0004 farads?
adell [148]

Answer:

The natural frequency will be 228.11 rad/sec

Explanation:

We have given Inductance L = 0.048 Henry

And the capacitance C = 0.0004 farad

We have to find natural frequency

When only inductor and capacitor is present in the circuit then it is known as LC circuit and  Natural frequency of LC circuit is given by \omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec

So the natural frequency will be 228.21

4 0
3 years ago
a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed
Juliette [100K]
  • Mass of the car (m) = 2000 Kg
  • Initial velocity (u) = 15 m/s
  • Force (F) = 10000 N
  • Time (t) = 3 s
  • Let the acceleration be a.
  • By using the formula, F = ma, we get,
  • 10000 N = 2000 Kg × a
  • or, a = 10000 N ÷ 2000 Kg
  • or, a = 5 m/s^2
  • Let the final velocity be v.
  • By using the formula, v = u + at, we get,
  • v = 15 m/s + 5 m/s^2 × 3 s
  • or, v = 15 m/s + 15 m/s
  • or, v = 30 m/s

<u>Answer</u><u>:</u>

<em><u>The </u></em><em><u>new </u></em><em><u>sp</u></em><em><u>e</u></em><em><u>ed </u></em><em><u>of </u></em><em><u>the </u></em><em><u>car </u></em><em><u>is </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>m/</u></em><em><u>s.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
3 years ago
What component of a longitudinal sound wave is analogous to a trough of a transverse wave?
anzhelika [568]

Explanation:

There are two components of a longitudinal sound wave which are compression and rarefaction. Similarly, there are two components of the transverse wave, the crest, and trough.

The crest of a wave is defined as the part that has a maximum value of displacement while the trough is defined as the part which corresponds to minimum displacement.

While compression is that space where the particles are close together while the rarefaction is that space where the particles are far apart from each other.

So, the refraction or the rarefied part of a longitudinal sound wave is analogous to a trough of a transverse wave.  

6 0
3 years ago
A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed int
Stells [14]

Answer:

A. The hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand = 1025 N

Explanation:

A.To determine the speed the hand must move with to break the board, the force workdone in breaking the board is found first.

Workdone = force × distance

Minimum force required = 870 N;

Distance moved by board/Deflection in order to break = 1.4 cm = 0.014 M

Workd done = 870 N × 0.014 m = 12.18 Nm or 12.18 J

This work done = Kinetic energy of the hand

Kinetic energy = mv²/2 ; where m is mass and v is velocity

Mass of hand = 0.50 Kg, velocity = ?, K.E. = 12.18 J

v² = 2 KE/m

v = √2KE/m

v = √(2 × 12.18/0.50)

v = 6.98 m/s

Therefore, the hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand

This can be determined using the equation of motion, v² = u² + 2as to find acceleration, since force = mass × acceleration

From the equation of motion, a = v² - u²/2s

At rest, v = 0, u = 6.98, s = 1.2 cm = 0.012 m

a = 0² - 6.98²/ 2 × 0.012

a = -2030 m/s²

Force = 2030 m/s² × 0. 50 kg = 1015 N

Therefore, Average force on the hand = 1025 N

3 0
3 years ago
Three point charges are arranged along the x-axis. Charge q1 = +3.00 uC is at the origin, and charge q2= -5.00 uC is at x= 0.200
artcher [175]
We have all the charges for q1, q2, and q3. 
Since k = 8.988x10^2, and N=m^2/c^2

F(1) = F (2on1) + F (3on1)

F(2on1) = k |q1 q2| / r(the distance between the two)^2
k^ | 3x10^-6 x -5 x 10^-6 |   / (.2m)^2
F(2on1) = 3.37 N

Since F1 is 7N,

F(1) = F (2on1) + F (3on1)
7N = 3.37 N + F (3on1)

Since it wil be going in the negative direction,
-7N = 3.37 N + F (3on1)
F(3on1) = -10.37N

F(3on1) = k |q1 q3| / r(the distance between the two)^2 
r^2 x F(3on1) = k |q1 q3| 
r = sqrt of k |q1 q3| / F(3on1) 
= .144 m (distance between q1 and q3)
0 - .144m 

So it's located in -.144m

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
6 0
3 years ago
Read 2 more answers
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