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Zina [86]
3 years ago
13

An ideal gas occupies a volume V at an absolute temperature T. If the volume is halved and the pressure kept constant, what will

happen to it's temperature?
a. It will halve to T/2.


b. It will increase to 3T.


c. It will increase to 2T.


d. It will remain the same.
Chemistry
1 answer:
Kruka [31]3 years ago
6 0

Answer:

It will be halve of T

Explanation:

V1 = V

T1 = T

V2 = ½V

T2 = x

V1/T1 = V2/T2

V/T = ½V/x

Vx = ½VT

2Vx = VT

2x = T

x = ½T

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Scorpion4ik [409]

Answer:

C. More NO2 and SO2 will form

Explanation:

Le Chatelier's Principle : It  predicts the behavior of equilibrium due to change in pressure , temperature , volume , concentration etc

It states that When external changes are introduced in the equilibrium then it will shift the equilibrium in a direction to reduce the change.

In given Reaction SO3 is introduced(increased) .

So equilibrium will shift in the direction where SO3 should be consumed(decreased)

Hence the equilibrium will go in backward direction , i.e

NO + SO_{3} \rightarrow NO_{2} + SO_{2}

So more and more Of NO2 and SO2 will form

7 0
3 years ago
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3 0
3 years ago
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Ksenya-84 [330]

Answer: The balance of the reaction shifts toward the endothermic reaction.

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8 0
3 years ago
What are geometric isomers?
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7 0
3 years ago
Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
iVinArrow [24]

The  number of atoms  of K that are in 235 g  of the compound  is

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 calculation

Step 1:  find the moles of K2S

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Step 2: multiply  2.136 moles  by no. of K atoms in K2S

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Step 3: use the Avogadro's  law to determine number of K atoms

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by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

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