An ideal gas occupies a volume V at an absolute temperature T. If the volume is halved and the pressure kept constant, what will
happen to it's temperature?
a. It will halve to T/2.
b. It will increase to 3T.
c. It will increase to 2T.
d. It will remain the same.
1 answer:
Answer:
It will be halve of T
Explanation:
V1 = V
T1 = T
V2 = ½V
T2 = x
V1/T1 = V2/T2
V/T = ½V/x
Vx = ½VT
2Vx = VT
2x = T
x = ½T
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