"a basic experiment involves a minimum of ________ participant group(s)."
1 answer:
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Answer:
Volume of chlorine = 61.943 mL
Explanation:
Given:
Volume of the water in the Pool = 18,000 gal
also,
1 gal = 3785.412 mL
thus,
Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL
Density of water = 1.00 g/mL
Therefore,
The mass of water in the pool = Volume × Density
or
The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g
in terms of million =
or
= 68.13747 g
also,
1 g of chlorine is present per million grams of water
thus,
chlorine present is 68.13747 g
Now,
volume =
or
Volume of chlorine =
or
Volume of chlorine = 61.943 mL
Answer:
784500 Joules
Explanation:
To start, you will need an equation to find the change in energy. This can be found by using or by using integrated heat capacities.
to find the mass of water,
1kg/L is the density of water.
Then,
Notice that all of the units do not cancel out properly, so some unit conversions are needed to find the correct answer.