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kirza4 [7]
3 years ago
13

"a basic experiment involves a minimum of ________ participant group(s)."

Chemistry
1 answer:
3241004551 [841]3 years ago
5 0
Answer: TWO.

At least two groups: treatment group and control group.

The treatment group is that is exposed to the different levels of the independent variable ( a medication for example), while the control group is not treated, so the researchers can compare the effect of the medication.
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Hydrogen chloride and oxygen react to form chlorine and water, like this:
leva [86]

Answer:

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

Explanation:

This is the reaction:

4 HCl (g) + O₂ (g)  ⇒ 2 Cl₂ (g)  + 2 H₂O(g)

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

8 0
3 years ago
Read 2 more answers
What trend in ionization energy occurs across a period on the periodic table? What causes this trend?
Lyrx [107]
The smaller the atomic radius in an element, the more ionization energy it will have. So when you go across the periodic table, the IE will decrease.
4 0
3 years ago
Which of the elements listed would have the greatest electronegativity?
disa [49]

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6 0
3 years ago
How many moles are in 2.4g of carbon dioxide (CO2)?
miv72 [106K]

Answer:

\boxed {\boxed {\sf 0.055 \ mol \ CO_2}}

Explanation:

To convert form grams to moles, the molar mass must be used. This is the mass (in grams) in 1 mole of a substance.

We can use the values on the Periodic Table. First, find the molar masses of the individual elements: carbon and oxygen.

  • C: 12.011 g/mol
  • O: 15.999 g/mol

Check for subscripts. The subscript of 2 after O means there are 2 oxygen atoms, so we have to multiply oxygen's molar mass by 2 before adding.

  • O₂: 2* (15.999 g/mol)=31.998 g/mol
  • CO₂: 12.011 g/mol + 31.998 g/mol =40.009 g/mol

Use the molar mass as a ratio.

\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}

Multiply by the given number of grams.

2.4 \ g \ CO_2 *\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}

Flip the fraction so the grams of carbon dioxide cancel.

2.4 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g\ CO_2}

2.4  *\frac { 1 \ mol \ CO_2}{44.009}

\frac { 2.4 \ mol \ CO_2}{44.009}= 0.0545342998 \ mol \ CO_2

The original measurement of grams has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

The ten thousandth place has a 5, so we round the 4 to a 5.

0.055 \ mol \ CO_2

2.4 grams of carbon dioxide is about 0.055 moles.

8 0
3 years ago
(12) Magnesium metal burns very brightly to produce heat and a white solid.
hjlf

Answer:

exothermic

Explanation:

heat/energy is released when it burns.

5 0
3 years ago
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