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Liono4ka [1.6K]
3 years ago
14

For the reaction: Cr2O7^2- + NH4^+ → Cr2O3 + N2, which is the oxidizing agent?

Chemistry
1 answer:
lord [1]3 years ago
3 0

Answer:

(NH4)2Cr2O7

Explanation:

Hope this somehow helped.

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Valence bond theory is inadequate for describing systems with multiple adjacent ______ that overlap, as in aromatic molecules. a
Alja [10]

A better explanation of these systems is given using molecular orbital theory.

<h3>What is the valence bond theory?</h3>

The valence bond theory hold that a  bond is formed by the sharing of two electron in a covalent bond. This bond does not account for certain systems that occur in multiple bonded systems where the simple two electron bonding model does not suffice.

Thus, valence bond theory is inadequate for describing systems with multiple adjacent  bonds that overlap, as in aromatic molecules. a better explanation of these systems is given using molecular orbital theory.

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7 0
1 year ago
The molecule hydrogen fluoride (HF) contains a polar bond H – F, where fluorine is more electronegative than hydrogen. Which is
slega [8]
The answer is going to be +H-F. Hope that helps you at all
3 0
3 years ago
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PLEASE HELP!!! - 15 Points
Xelga [282]
It makes plastics easier to shape.
6 0
3 years ago
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A buffer is made with sodium acetate (CH3COONa) and acetic acid (CH3COOH); the Ka for acetic acid is 1.80×10−5. The pH of the bu
Goryan [66]

Answer:

B. 0.174

Explanation:

A buffer is formed by a weak acid (CH₃COOH) and its conjugate base (CH₃COO⁻, coming from sodium acetate). We can calculate the pH of this buffer using the Henderson-Hasselbalch equation.

pH = pKa + log [CH₃COO⁻]/[CH₃COOH]

pH - pKa = log [CH₃COO⁻]/[CH₃COOH]

3.98 - (-log 1.80 × 10⁻⁵) = log [CH₃COO⁻]/[CH₃COOH]

-0.760 = log [CH₃COO⁻]/[CH₃COOH]

[CH₃COO⁻]/[CH₃COOH] = anti log (-0.760)

[CH₃COO⁻]/[CH₃COOH] = 0.174

4 0
3 years ago
what volume (in ml) of 1.508 m h3po4 (aq) would be required to react completely with 11.73 ml of 1.006 m ca(oh)2? (aq)
alexdok [17]

The amount of 4.86 ml needed to completely react with 11.73 ml of 1.006 m ca(oh)2 is 4.86 ml.

given data to  be calculated:-

Ca3(PO4)2 (s) + 6H2O can be used to calculate this: 3Ca(OH)2 (aq) + 2H3PO4 (aq) (l)

ca moles (OH)

2  present 11.00 moles of H3PO4 are required; 7.33 moles of H3PO4 in a volume of ml are required; 7.33/1.508 = 4.86.

<h3>How do moles react to an increase in volume?</h3>

The direction that creates more moles of gas benefits from an increase in volume, and since there are more moles of products in this case, the reaction will shift to the right and produce more moles of products.

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6 0
1 year ago
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