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Triss [41]
3 years ago
6

How do you multiply two numbers that are written in scientific notation format?

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer:

To multiply two numbers in scientific notation, multiply their coefficients and add their exponents. To divide two numbers in scientific notation, divide their coefficients and subtract their exponents. In either case, the answer must be converted to scientific notation.

Step-by-step explanation:

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In the graph, what does A represent?<br>A. Foci<br>B. Minor Axis<br>C. Major Axis<br>D. Vertices
Dimas [21]

Answer: A. Foci

Step-by-step explanation:

6 0
3 years ago
The equation of line c is y–5=
Paraphin [41]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the "c" equation

y-5=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{3}{5}}(x-7)\qquad \impliedby \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}

so line "d" is a line with a slope of 3/5 and passes through (1,-1)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{5}}(x-\stackrel{x_1}{1})\implies y+1=\cfrac{3}{5}(x-1) \\\\\\ y+1=\cfrac{3}{5}x-\cfrac{3}{5}\implies y=\cfrac{3}{5}x-\cfrac{3}{5}-1\implies y=\cfrac{3}{5}x-\cfrac{8}{5}

8 0
2 years ago
Read 2 more answers
I need help on this question ​
dlinn [17]

Answer: number 3

Step-by-step explanation:

7 0
2 years ago
!!! TIME SENSITIVE !!! Determine the period.
rosijanka [135]

Answer:

A wave period is the measure of the time it takes for the wave cycle to complete.

The period of the wave is 2 seconds.

3 0
2 years ago
(X-3) (2x-3)= (x-3) (x+1) solve for x
yanalaym [24]

(x  - 3)(2x - 3) = (x - 3)(x + 1)

Do the multiplication both sides,

2 {x}^{2}  - 9x + 9 =  {x}^{2}  - 2x - 3

Arrange the terms to LHS according to their variables,

2 {x}^{2}  -  {x}^{2}  - 9x  +  2x + 9 - 3 = 0 \\  {x}^{2}  - 7x  + 6 = 0


Factorise this polynomial

{x}^{2}  - 6x - 6x + 6 = 0 \\ x(x - 6) - (x - 6) = 0 \\ (x - 1)(x - 6) = 0


So what we notice here is when you're multiplying two numbers you're getting 0 as answer.

So one of them must be 0.

If (x-1) is 0
then x = 1

similarly,

x-6=0

then, x= 6.


So the possible values of x are 1 and 6.
7 0
3 years ago
Read 2 more answers
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