Here are some examples for those type of reactions.
<span>
Combustion reaction: CH4(g) + 2 O2(g) --> CO2(g) + 2 H2O(l)
</span><span>
Decomposition reaction: CaCO3(s) ---> CaO(s) + CO2(g)
</span><span>Double replacement: AgNO3(aq) + NaCl(aq) ---> AgCl(s) + NaNO3(aq)
</span>One common thing in all is that they are reactions. They have reactants to form new substances called product.
2,8,3 because Aluminium has the Atomic Number 13
Answer:
The carrying capacity of this population would be 125 we know this because we see that this number occur multiple times and seems to be the tipping point after which the number of the population always go down
Answer:
1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂
Fe + 2HCl ⟶ FeCl₂ + H₂
2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g
Explanation:
1) Possible reactions
2Al + 6HCl ⟶ 2AlCl₃ + 3H₂
Fe + 2HCl ⟶ FeCl₂ + H₂
2) Mass of each metal
a) Mass of Cu
The waste was the unreacted copper.
Mass of Cu = 2.5 g
b) Masses of Al and Fe
We have two relations
:
Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g
H₂ from Al + H₂ from Fe = 6.38 L at NTP
i) Calculate the moles of H₂
NTP is 20 °C and 1 atm.
(ii) Solve the relationship
Let x = mass of Al. Then
7.5 - x = mass of Fe
Moles of Al = x/27
Moles of Fe = (7.5 - x)/56
Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x
/18
Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56
∴ x/18 + (7.5 - x)/56 = 0.2652
56x + 18(7.5 - x) = 267.3
56x + 135 - 18x = 267.3
38x = 132.3
x = 3.5 g
Mass of Al = 3.5 g
Mass of Fe = 7.5 g - 3.5 g = 4.0 g
The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g
Just multiply 151 x 0.0001
That will equal:
0.00151 km or if you want to round it then it would be 0.02km