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s2008m [1.1K]
3 years ago
6

Find 4 1/5 · 7 2/3 plz answer quickly!

Mathematics
2 answers:
Naddik [55]3 years ago
7 0
Answer:

32 1/5

Explanation:
cricket20 [7]3 years ago
4 0
Answer:
32 1/5

Explanation:
Step 1 - Convert each mixed number into an improper fraction

4 1/5 • 7 2/3
21/5 • 23/3

Step 2 - Multiply straight across and simplify

21/5 • 23/3
483/15
161/5
32 1/5
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What is the answer? 5(6x-2) = -250
faust18 [17]

Answer:

x = -8

Step-by-step explanation:

5(6x-2) = -250

30x - 10 = -250

30x/(30) = -240/(30)

x = -8

4 0
3 years ago
Read 2 more answers
Can someone walk me through this?
shepuryov [24]
I hope this helps you



Ax+By=C



By=C-Ax


y=C/B-A/Bx


m= -A/B
8 0
3 years ago
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
What is the product of the 2 solutions of the equation x^2+3x-21=0
Advocard [28]
X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2

2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21

Answer: the product of the 2 solutions of this equation is -21
3 0
3 years ago
I need help please, I will give brainliest to the first person that answers. Also extra points.
Papessa [141]

Answer:

B)

a + c = 7

9a + 4c = $43

Step-by-step explanation:

There're 7 tickets which were bough in total. Two different types of tickets, one which represented children, the other for adults. The adult ticket is represented by <em>a </em>and is 9 dollars. The children's ticket is represented by <em>c </em>and is 4 dollars.

<em>Have a nice April Fool's XD.</em>

5 0
2 years ago
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