Answer:
23.8g of sodium phosphate are formed
Explanation:
Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:
3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂
<em>3 moles of sodium produce 1 mole of sodium phosphate</em>
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To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:
<em>Moles Na -Molar mass: 22.99g/mol-</em>
10g * (1mol / 22.99g) = 0.435 moles Na
<em>Moles Na₃PO₄:</em>
0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄
<em>Mass Na₃PO₄ -Molar mass: 163.94g/mol-</em>
0.145 moles Na₃PO₄ * (163.94g/mol) =
<h3>23.8g of sodium phosphate are formed</h3>
Answer:
elements
Matter that has only one kind of atom is called an element. Gold, copper, oxygen, and mercury are examples of elements. Most matter is made up of two or more different kinds of atoms that are chemically combined. This kind of matter is called a compound.
Explanation:
Answer:
[H⁺] = 1.0 x 10⁻¹² M.
Explanation:
∵ [H⁺][OH⁻] = 10⁻¹⁴.
[OH⁻] = 1 x 10⁻² mol/L.
∴ [H⁺] = 10⁻¹⁴/[OH⁻] = (10⁻¹⁴)/(1 x 10⁻² mol/L) = 1.0 x 10⁻¹² M.
∵ pH = - log[H⁺] = - log(1.0 x 10⁻¹² M) = 12.0.
∴ The solution is basic, since pH id higher than 7 and also the [OH⁻] > [H⁺].
I think- IDK
Answer:
in nuclear fusion deep in the interiors of stars
Explanation:
Nuclear fusion -
It is the type of reaction , where two or more atomic nuclei of the atom merges together to release two or more different nuclei along with some subatomic particles , is referred to as a nuclear fusion reaction .
The reaction can very well be done on stars , because of very high energy .
Hence , a nuclear fusion occurs deep inside the stars .
Explanation:
Chemical reaction equation for the give decomposition of 
is as follows:.
And, initially only is present.
The given data is as follows.
= 2.3 atm at equilibrium
= 0.69 atm
Therefore,
= 0.23 aatm
So, = 2.3 - 2(0.23)
= 1.84 atm
Now, expression for 
will be as follows.
= 
= 0.0224
or, 
Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 
.
