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anygoal [31]
3 years ago
7

In the future, a spaceship has traveled three percent of the distance to a space station. If the ship has traveled 2.9 x 10^7 mi

les so far, how much further does the ship have to travel to its destination?
Physics
1 answer:
leva [86]3 years ago
6 0

Answer:

9.38 * 10^8 miles

Explanation:

The spaceship has traveled 3% of the distance to a space station and it has traveled 2.9 * 10^7 miles.

Let the total distance from the ship's starting point to the space station be x.

This means that:

\frac{3}{100}  * x = 2.9 * 10^7\\\\=> x = \frac{2.9 * 10^7 * 100 }{3} \\\\x = 9.67 * 10^8 miles

The total distance to be traveled is 9.67 * 10^8 miles.

Therefore, the distance left to travel is:

9.67 * 10^8 - 2.9 * 19^7\\\\= 9.38 * 10^8 miles

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A girl stand 5m away from a large plane mirror.How far must she walk ti be 2m away from her image?​
KonstantinChe [14]

Answer:

3m

Explanation:

If a girl is 5m away from a mirror, she needs to walk a further 3m to be 2m away from her image.

5m-3m = 2m

4 0
2 years ago
What is the difference between speed and velocity?
ElenaW [278]
B - speed and direction are combined in another quantity, called velocity. It can be thought of as its speed in a particular direction. Speed is the corresponding scalar quantity, because it does not have a direction.
5 0
3 years ago
A proton is moving at 425 m/s. (a) How much work must be done on it to stop it? (A proton has a mass of 1.67×10−27 kg.) (b) Assu
Tpy6a [65]

Answer:

a)1.51*10^-22joules b) 1.89*10^-7m

Explanation:

Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules

b) net force acting to stop the proton = 8.01*10^-16

Work done needed to stop the proton = net force acting opposite the motion * distance

Distance covered = need work done/ net force

Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m

8 0
4 years ago
A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
Tatiana [17]

Answer:

<u>We are given:</u>

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

<u>Solving for initial velocity:</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

8 0
3 years ago
1. The thin top layer of the crust is called the Crust. What are the two types of
kolbaska11 [484]
Oceanic and continental
8 0
3 years ago
Read 2 more answers
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