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anygoal [31]
3 years ago
7

In the future, a spaceship has traveled three percent of the distance to a space station. If the ship has traveled 2.9 x 10^7 mi

les so far, how much further does the ship have to travel to its destination?
Physics
1 answer:
leva [86]3 years ago
6 0

Answer:

9.38 * 10^8 miles

Explanation:

The spaceship has traveled 3% of the distance to a space station and it has traveled 2.9 * 10^7 miles.

Let the total distance from the ship's starting point to the space station be x.

This means that:

\frac{3}{100}  * x = 2.9 * 10^7\\\\=> x = \frac{2.9 * 10^7 * 100 }{3} \\\\x = 9.67 * 10^8 miles

The total distance to be traveled is 9.67 * 10^8 miles.

Therefore, the distance left to travel is:

9.67 * 10^8 - 2.9 * 19^7\\\\= 9.38 * 10^8 miles

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8 0
3 years ago
A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the
Elan Coil [88]

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/s^{2}

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

s=ut+\frac{1}{2}at^{2}

15.3=3t+2.5t^{2}

2.5t^{2}+3t-15.3=0

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

v=u+at

v=3+1.945*5

v=3+9.72

v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

7 0
3 years ago
2. Why do you need eggs to make manynaise? (yo
anastassius [24]

Answer:

to make it fluffy

Explanation:

6 0
3 years ago
A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e
mafiozo [28]

Answer:

x = 0.974 L

Explanation:

given,

length of inclination of log = 30°

mass of log = 200 Kg

rock is located at = 0.6 L

L is the length of the log

mass of engineer = 53.5 Kg

let x be the distance from left at which log is horizontal.

For log to be horizontal system should be in equilibrium

 ∑ M = 0

mass of the log will be concentrated at the center  

distance of rock from CM of log = 0.1 L

now,

∑ M = 0

m_{log} g \times 0.1 L = m_{engineer} g \times (x - 0.6 L)

200 \times 0.1 L = 53.5 \times (x - 0.6 L)

0.374 L =x - 0.6 L

       x = 0.974 L

hence, distance of the engineer from the left side is equal to x = 0.974 L

7 0
3 years ago
Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strengt
Nesterboy [21]
V=Ed=0.20\times 6=1.20
8 0
3 years ago
Read 2 more answers
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