What is the role of the kinetic theory of matter in the process of solutes being dissolved into solvents?

Chemistry

1 answer:

hjlf3 years ago

6 0

Answer:

i'd say the second choice.

Explanation:

the rise in temperature causes the particles to vibrate causing motion. they collide thus resulting to the weakening of the particles.

hope it is of use to you.

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Consider the reaction hc2h3o2(aq) h2o(l) → h3o (aq) c2h3o2–(aq). Which species is the conjugate acid?a. C2h3o2-(aq)b. H2o(l)c. H

saul85 [17]

The species that is the conjugate acid is HC₂H₃O₂(aq). The correct option is d.

<h3>What are conjugate acid?</h3>

Conjugates acids are those acids which are made when an acid donates a proton to a base according to Bronsted Lowry theory.

In other words, we can say that it is an acid with hydrogen ion. An example is water (base) reacting with an acid to form the hydronium ion (conjugate acid).

Thus, the correct option is d, HC₂H₃O₂(aq).

Learn more about conjugate acid

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1 year ago

Hydrogen is a gas at a room temperature, but it is found with the alkali metals in group 1 (1A) on the periodic table. Which is

poizon [28]

Elements were grouped on their properties and behaviors, so hydrogen resides with the alkali metals in group 1 (1A) because it has only 1 valence electron, like the metals in that group.

4 0

3 years ago

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Brums [2.3K]

Answer:

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8 0

3 years ago

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A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$