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3 years ago

8

Now move points C, D, and E on the circle, and note the interior angle measurements for the quadrilateral in the table below. No

tice that m∠B is predetermined, so set that angle measure first.

1 answer:

labwork [276]3 years ago

5 0

Answer:

Interior angle

measures of any n-gon, where n represents the

number of sides of the polygon, by multiplying

(n - 2) 180°.

Hope this helps :D

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What is 80%of 40equals what

kari74 [83]

If you would like to solve 80% of 40, you can do this using the following steps:

80% of 40 = 80% * 40 = 80/100 * 40 = 32

The correct result would be 32.

7 0

3 years ago

Read 2 more answers

Drag the point A to the location indicated in each scenario to complete each statement.

Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>

If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>

If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>

If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b is positive

Therefore;

c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

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2 years ago

Write the integer that best represents 23 degrees below zero.

Kitty [74]

If it was 23 degrees below zero it would be -23 degrees

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3 years ago

X plus 1/3 equals nine enter your answer in the box in simplest form

LekaFEV [45]

$= > x + \frac{1}{3} = 9$

$\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}$

$= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}$

Hence,

$Value \: \: \: of \: \: x \: \: is \: \frac{26}{3} \: \: \: or \: \: \: 8. \bar{6}$

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3 years ago

Need the answer right now

hodyreva [135]

Answer:

Diameter is 19

Step-by-step explanation:

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3 years ago