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3 years ago

What is the pOH of a base with a OH- concentration of 0.0500 x 10-11 M? PLEASEEEEEE ASAP

Chemistry

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

poH= -log(oh^-)

= - log (0.500* 10^-11)

= =- log 0.5 + log (10^-11)

= -( -0.30 +(-11))

=+ 11.3

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Tcecarenko [31]

The balanced chemical reactions are:

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Further Explanation:

The following reactions will undergo double displacement where the metal cations in each compound are exchanged and form new products.

For reaction 1, the compounds involved are nitrates and chlorides. To determine the states of the products, the solubility rules for nitrates and chlorides must be followed:

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Therefore, the products will have the following characteristics:

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For reaction 2, the compounds involved are phosphates and chlorides. The solubility rules for phosphates and chlorides are as follows:

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Insoluble substances are denoted by the symbols (s) in a chemical equation. The soluble substances are denoted as <em>(aq).</em>

Learn More

Learn more about solubility brainly.com/question/1163248
Learn more about solubility rules brainly.com/question/1447161
Learn more about net ionic equations brainly.com/question/12980075

Keywords: solubility rules, precipitation reaction

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3 years ago

Water is a produced when 30.0 grams of hydrogen reacts with 80.0 grams of oxygen what is the limiting reagent

irakobra [83]

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number of O₂ moles - 80.0 g / 32 g/mol = 2.5 mol
limiting reactant is the reagent in which only a fraction is used up in the reaction
if H₂ is the limiting reactant
if 2 mol of H₂ requires 1 mol of O₂
then 15 mol of H₂ requires 1/2 x 15.0 = 7.5 mol of O₂
but only 2.5 mol of O₂ is required
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