-- 236 of them make 1 cup
-- 946 of them make 1 quart
-- the volume of a tiny cube that's 1 centimeter along each edge
-- 16.4 of them in a little cube that's 1 inch along
-- 4.9 of them make a standard cooking teaspoon
-- a perfume that cost $50 an ounce would cost $1.69 per milliliter
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
A suitable calculator shows the score of
46.0 separates the bottom 26% from the top 74%.
Step-by-step explanation:
I really don't know sorry