Answer:
220g of CO2
Explanation:
Step 1:
The balanced equation for the reaction.
2C5H11OH + 15O2 —> 10CO2 + 12H2O
Step 2:
Determination of the number of mole of CO2 produced by burning 1 mole of C5H11OH.
From the balanced equation above,
2 moles of C5H11OH produced 10 moles CO2.
Therefore, 1 mole of C5H11OH will produce = (1 x 10)/2 = 5 moles of CO2.
Therefore, 5 moles of CO2 is produced from the reaction.
Step 3:
Conversion of 5 moles of CO2 to grams.
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Number of mole of CO2 = 5 moles
Mass of CO2 =...?
Mass = mole x molar mass
Mass of CO2 = 5 x 44
Mass of CO2 = 220g.
Therefore, 220g of CO2 were obtained from the reaction.
