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4 years ago

Why do cells carry out cellular respiration

1 answer:

8 0

Plants and animals carry out cellular respiration, but only plants conduct photosynthesis. Cellular respiration is the process in which a cell uses oxygen to convert glucose, a simple sugar, into the energy-carrying molecule, adenosine triphosphate (ATP).

hope this helps :)

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Is a book sitting high upon a shelf a balanced force or an unbalanced force

Art [367]

Balanced force I think

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3 years ago

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3. Write balanced ionic equations to show the dissolution of the following compounds in water: a) magnesium chloride

melamori03 [73]

Answer:

MgCl2 + H2O

Explanation:

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2 years ago

A (12), B (8), C (4) out of these three elements, which two elements would show similar chemical properties?

fiasKO [112]

Answer: A and C

Explanation:

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3 years ago

The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (

harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as $Rate=k[H_2O_2]$

Part b: The integrated Rate Law is given as $[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c: The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

$Rate=k[H_2O_2]$

Part b

Integrated Rate Law

The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d

Concentration after 4000 s is given as

$-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M$

Concentration after 4000 s is 0.043 M.

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3 years ago

3.25*10^25 atoms of neon gas equals how many moles of neon gas?

charle [14.2K]

Mole: the amount of a substance that contains 6.02 x 10. 23 respective particles of that substance. Avogadro's number: 6.02 x 10. 23. Molar Mass: the mass of one mole of an element. CONVERSION FACTORS: 1 mole = 6.02 x 10. 23 atoms 1 mole = atomic mass (g). Try: 1. How many atoms are in 6.5moles of zinc

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3 years ago

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