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Troyanec [42]
3 years ago
15

Write and balance the following equation:

Chemistry
1 answer:
rodikova [14]3 years ago
7 0

Answer:

The answer is 2Al + Pb(NO3)2 ->2AlNO3 + Pb.

Explanation:

Al represents <em>A</em><em>l</em><em>u</em><em>m</em><em>i</em><em>n</em><em>i</em><em>u</em><em>m</em><em> </em><em>.</em>

Pb(II) represents <em>L</em><em>e</em><em>a</em><em>d</em><em> </em><em>(</em><em>I</em><em>l</em><em>)</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em> </em><em>.</em>

NO3 represents<em> </em><em>N</em><em>i</em><em>t</em><em>r</em><em>a</em><em>t</em><em>e</em><em>s</em><em> </em><em>i</em><em>o</em><em>n</em><em>s</em><em> </em><em>.</em>

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Answer:

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Explanation:

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If 5.0 g of copper metal reacts with a solution of silver nitrate, how many grams of silver metal are recovered?
sukhopar [10]

Answer:

16.9g

Explanation:Cu+2AgNO3→2Ag+Cu(NO3)2  

Cu will likely have a +2 oxidation state. It is higher in the activity series than Ag, so it is a stronger reducing agent and will reduce Ag in a displacement reaction. Then you need to balance the coefficients knowing than NO3 is -1 and Ag is +1.

Then to calculate the theoretical yield you need to compare moles of the reactants:

m(Cu)=5g

M(Cu)=63.55

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By comparing coefficients you require twice as much silver: 0.157mol

n(Ag)=0.157

M(Ag)=107.86

m(Ag)=0.157x107.86=16.9g

Hence, the theoretical yield of this reaction would be 16.9g

3 0
3 years ago
Need help on this really bad!
timofeeve [1]

Answer:

Help your self

Explanation:

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2 years ago
Order the density of the layers of the Earth from lowest density to highest
tatiyna

Answer:

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balandron [24]

Answer:

D. Anti-periplanar

Explanation:

In the <u>second step</u> of the intramolecular William Ether Synthesis mechanism (figure 1) we will have the attack of the negative charge of the oxygen to the carbon bond to the Br. At the same time the Br leaves, so a bond would be broken (the <u>C-Br</u> bond) and a bond would be formed (the <u>C-O</u> bond).

Now, this process can happen only if the <u>attack</u> and the <u>leaving group </u>has an anti configuration (figure 2). In an anti configuration the <u>nucleophile</u> and the <u>leaving group</u> would have <u>opposite directions</u>.

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