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Sphinxa [80]
4 years ago
8

Select the physical properties. Select all that apply.

Chemistry
2 answers:
Darya [45]4 years ago
6 0
I mean the answer is -2 m/s^2
Aleonysh [2.5K]4 years ago
3 0

Answer: chopping wood

Heating water

Explanation:

Right on edge

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The reactants in a chemical equation have 3 carbon atoms, 6 oxygen atoms, and 4 hydrogen atoms. In order to follow the conservat
Rzqust [24]

Answer:

the answer of rhe question is B

5 0
3 years ago
What is the estimated effective nuclear charge, Z eff, experienced by an electron in a 3p orbital of a chlorine atom?
Lunna [17]
Because 3pd hope  it helps 
8 0
3 years ago
PLEASE ANSWER
RoseWind [281]

It is a radio wave

Explanation:

The energy of an electromagnetic waves is related to its frequency by the equation:

E=hf

where

h is the Planck constant

f is the frequency of the wave

We notice that the energy of an electromagnetic wave is proportional to its frequency. This means that waves with higher frequencies, such as gamma rays, x-rays, are more energetic, while waves with lower frequencies, such as microwave and radio waves, are the less energetic.

In this case, we want to find the frequency of a wave with energy

E = 0.000001 eV

Converting into Joules,

E=1\cdot 10^{-6} eV \cdot 1.6\cdot 10^{-19} J/eV=1.6\cdot 10^{-25} J

Solving for the frequency,

f=\frac{E}{h}=\frac{1.6\cdot 10^{-25}}{6.63\cdot 10^{-34}}=2.4\cdot 10^8 Hz = 240 MHz

Which falls in the range of frequency of radio waves.

Learn more about electromagnetic waves:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

4 0
3 years ago
What volume will 2.00 moles of nitrogen occupy at 720 torr and 20C?
bija089 [108]

Answer:

50.62L

Explanation:

1torr= 0.00132atm

P=720torr = 0.95atm

V= 20°C= 20+273= 293K

PV=nRT

R=0.08206L-atm/mol-K

0.95×V= 2×0.08206×293

V= 2×0.08206×293/ 0.95

V= 50.62L

3 0
4 years ago
you have to prepare a ph 5.03 buffer, and you have the following 0.10m solutions available: hcooh, hcoona, ch3cooh, ch3coona, hc
TiliK225 [7]

Solution :

The buffer is the one that contains weak acid (the $\text{pK}_a$ is nearly equal to the required pH) and the salt of its conjugate base.

The $\text{pK}_a$  values of the given weak acids are as follows :

HCOOH : $\text{pK}_a$  = 3.744

$CH_3COOH : pK_a = 4.756$

HCN : $\text{pK}_a$ = 9.21

Since the required pH is 5.03, the suitable buffer is the mixture of the acetic acid and the salt of its conjugate base.

Let suppose the volumes of $CH_3COOH$ and $CH_3COONa$ are x and y mL respectively.

So the total volume of the buffer is 1000 mL.

∴   x+ y = 1000  ................(1)

Writing the Henderson-Hasselbalch equation for the given buffer solution :

$pH = pK_a + \log \ \frac{[CH_3COONa]}{[CH_3COOH]}$   .............(2)

$5.03 = 4.756 + \log \ \frac{\left(\frac{y \ mL \times 0.10 \ M}{(x+y) \ mL}\right)}{\left(\frac{x \ mL \times 0.10 \ M}{(x+y) \ mL}\right)}$

$5.03 = 4.756+ \log \frac{y}{x}$

$\frac{y}{x}=10^{5.03-4.756}$

y = 1.9 x

Substituting the values of y in equation (1), we get

x + 1.9 x = 1000

x = 345

Putting the value of x in (1), we get

345 + y = 1000

y = 655

Therefore the volume of $CH_3COOH$ is 345 mL and the volume of $CH_3COONa$ is 655 mL.

5 0
3 years ago
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