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Leni [432]
3 years ago
7

A 0.250 g sample of hydrocarbon (containing only carbon and hydrogen) undergoes complete combustion to produce 0.845 g of CO2 an

d 0.173 g of H2O. What is the empirical formula of this compound?
Chemistry
1 answer:
melomori [17]3 years ago
5 0

Answer:

CH

Explanation:

We have to obtain the mass of carbon and hydrogen in CO2 and H2O respectively.

For carbon in CO2;

0.845 * 12/44 = 0.23 g

For hydrogen in H20;

0.173 * 2/18 = 0.019 g

We convert the masses to moles of carbon and hydrogen

For carbon - 0.23/ 12 = 0.019 moles

For hydrogen - 0.019/1 = 0.019 moles

Dividing by 0.019 moles for carbon and hydrogen we have the emperical formula of the compound as CH

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7 0
3 years ago
Why are biopharmaceuticals in high demand?
elena-s [515]

Answer:

the market is largely driven by the growing population, increasing burden of chronic disease, and rising inclination toward targeted therapy.

Explanation:

also, the huge demand of biopharmaceutical is facilitated by an accelerating focus in research and related investment.

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3 years ago
(Exercise 5.2.14 modified) A common method used to produce bleach (sodium hypochlorite) is by the reaction Cl2 + 2NaOH  NaCl +
Oksana_A [137]

Answer:

Chlorine is limiting reactant

Explanation:

Based on the reaction:

Cl₂ + 2NaOH → NaClO + NaCl + H₂O

<em>1 mole of chlorine reacts with 2 moles of NaOH</em>

<em />

To find limiting reactant, we need to determine the moles of the reactants:

<em />

<em>Moles Cl₂ -Molar mass: 70.9g/mol-:</em>

800lb Cl₂ * (453.6g / 1lb) * (1mol / 70.90g) =

5118 moles Cl₂

<em>Moles NaOH -Molar mass: 40g/mol-:</em>

1200lb NaOH * (453.6g / 1lb) * (1mol / 40g) =

13608 moles NaOH

For a complete reaction of 13608 moles of NaOH you need:

13608 moles NaOH * (1mol Cl₂ / 2 moles NaOH) = 6804 moles of Cl₂

As the solution contains just 5118 moles of chlorine,

<h3>Chlorine is limiting reactant</h3>
8 0
3 years ago
A 51.9g sample of iron, which has a specific heat capacity of 0.449·J·g?1°C?1, is put into a calorimeter (see sketch at right) t
Ghella [55]

Answer:

the initial temperature of the iron sample is Ti = 90,36 °C

Explanation:

Assuming the calorimeter has no heat loss to the surroundings:

Q w + Q iron = 0

Also when the T stops changing means an equilibrium has been reached and therefore, in that moment, the temperature of the water is the same that the iron ( final temperature of water= final temperature of iron = T )  

Assuming Q= m*c*( T- Tir)  

mc*cc*(T-Tc)+mir*cir*(T - Tir) = 0

 Tir = 20.3 °C + 300 g * 4.186 J/g°C * (20.3 C - 19 °C) / ( 51.9 g * 0.449 J/g°C )

 Tir = 90.36 °C

Note :

- The specific heat capacity of water is assumed 1 cal/g°C = 4.186 J/g°C  

- We assume no reaction between iron and water

7 0
3 years ago
What do you call all water on earth surface
kap26 [50]

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Hydrosphere

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