Answer:
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Answer:
0.767 moles of ammonium phosphate are produced
Explanation:
The reaction of ammona (NH3), with phosphoric acid is:
3 NH3 + H3PO4 → (NH4)3PO4
<em>Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.</em>
<em />
If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:
2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =
<h3>0.767 moles of ammonium phosphate are produced</h3>
<em />
High to low is what your looking for
Answer:
0.257 L
Explanation:
The values missing in the question has been assumed with common sense so that the concept could be applied
Initial volume of the AICI3 solution
Initial Molarity of the solution
Final molarity of the solution
Final volume of the solution
From Law of Dilution,
Final Volume of the solution 
Answer:
I have no Idea please give more context to your question.
Explanation: