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docker41 [41]
3 years ago
15

At constant temperature, a sample of helium at 760. torr in a closed container was compressed 5) from 5.00 L to 3.00 L, with no

change in amount of gas or temperature. What was the new pressure exerted by the helium on its container?
A) 3820 torr
B) 1270 torr
C) 800.torr
D)15.0 torr
E) 2280 torr
Chemistry
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

B) 1270 torr

Explanation:

Given data

  • Initial volume (V₁): 5.00 L
  • Initial pressure (P₁): 760 torr
  • Final volume (V₂): 3.00 L
  • Final pressure (P₂): ?

We can find the final pressure using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 760 torr × 5.00 L/3.00 L

P₂ = 1.27 × 10³ torr = 1270 torr

The final pressure is 1270 torr.

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Consider the following operations on the number 7.02 times 10^-2. Without using a calculator, decide which would give a signific
mariarad [96]

Answer: (a). Significantly Larger value

(b). Significantly Smaller value

(c). Significantly Larger value

(d). Significantly Smaller value

Explanation:

This is quite a dicey  question to analyze, let us not get too carried away with the simplicity of the mathematical signs involved.

Given that 7.02 × 10⁻² is the number to be compared with.

(a).  7.02 × 10⁻² + 6.10 × 10⁵

from this, we can see a very large number being added to the base number involved, although the base number is carrying a negative power, it does not affect the other greatly.

ANS: the sum would give a significantly larger value

(b). 7.02 × 10⁻² - 6.10 × 10⁵

Here, we can see a very large number subtracted from the base number having a negative power.

the subtraction of this numbers gives a Significantly smaller value than the base number i.e. 7.02 × 10⁻²

ANS: Significantly smaller value

(c). 7.02 × 10⁻² × 6.10 × 10⁵

we would solve this from our basic knowledge of indices

where ⇒ (10ᵃ × 10ᵇ = 10ᵃ⁺ᵇ)

we have,

7.02 × 10⁻² × 6.10 × 10⁵ = (7.02 × 6.10) × 10⁻²⁺⁵ = (7.02 × 6.10) × 10³

this final value (multiplication value) gives a Significantly larger value.

ANS: Significantly larger value

(d). 7.02 × 10⁻² ÷ 6.10 × 10⁵

Also, we apply the indices rule for Division

where ⇒ (10ᵃ ÷ 10ᵇ = 10ᵃ⁻ᵇ)

i.e. 7.02 × 10⁻² ÷ 6.10 × 10⁵ = (7.02 × 6.10) × 10⁻²⁻⁺⁵ = (7.02 × 6.10) × 10⁻⁷

this final value gives a Significantly Smaller value

ANS: Significantly Smaller value

cheers i hope this helps.

7 0
3 years ago
Chopping onions makes you cry because when you cut into an onion you break its cells. this releases sulfenic acids, which lead t
ruslelena [56]
Whats the question ?
8 0
3 years ago
Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

5 0
3 years ago
How many moles of nitrogen gas will occupy a volume of .5L at 1.0atm and 298K
hammer [34]
 <span>Use the Ideal law Equation :

P.V= n.R.T 

V = 0.5 L

P = 1.0 atm

</span><span>R= 0.0821 L*atm/mol*K 
</span>
<span>n = R*T/P*V 

</span><span>P*V= n*R*T 
</span>
1.0 * 0.5 = n *<span>0.0821*298

0,5 = n* 24.4658

n = 0,5 / 24.4658

n =0.0204 moles


</span>
8 0
3 years ago
A sample of water is mixed with a surfactant.what will most likely happen to the viscosity of the water?
GenaCL600 [577]
The viscosity will decrease
5 0
3 years ago
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