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meriva
3 years ago
15

[2x+5]=3x+4 what is the solution

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

x=-1

Step-by-step explanation:

2x+5=3x+4

    -4       -4

2x+1=3x

-2x  -2x

1=-x

1/-1 =-x/-1

-1=x

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What is the solution to the equation below?<br> 1.5 (2x+ 5) +2.5 = 1.5 (-2x + 7)= 0.5
Anarel [89]
Sorry for my writing
7 0
3 years ago
Find the range of the relation below, then determine whether the relation is a function.
Morgarella [4.7K]

Answer:

C

Step-by-step explanation:

It is a function because it passes the vertical line test and Xs do not repeat, then count out the Y-values which are the range.

4 0
3 years ago
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
If A={2,3,5,7} and B={2,4,6,8} then what is AnB?​
gregori [183]

Answer:

  • A∩B = {2}

Step-by-step explanation:

It asks for the common set of A and B.

<u>There only one element common to both the given sets:</u>

  • A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}
6 0
3 years ago
Read 2 more answers
Somebody help me with this please!!
Slav-nsk [51]

Notice the following pattern:

2 - 0 = 2

6 - 2  = 4

12 - 6 = 6

20 - 12 = 8

It's reasonable to assume that consecutive terms in the sequence differ by increasing multiples of 2, so that for the next number (call it x) we expect to see

x - 20 = 10  ==>  x = 30

and for the number after that (call it y) we would see

y - x = y - 30 = 12  ==>  y = 42

4 0
3 years ago
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