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3 years ago

Factorise f²-f-20 step by step

Mathematics

2 answers:

dlinn [17]3 years ago

8 0

Answer:

(f+4)(f−5)

Step-by-step explanation:

The middle number is -1 and the last number is -20.

Factoring means we want something like

(f+_)(f+_)

We need two numbers that...

Add together to get -1

Multiply together to get -20

4+-5 = -1

4*-5 = -20

Fill in the blanks in

(f+_)(f+_)

with 4 and -5 to get...

(f+4)(f-5)

Naily [24]3 years ago

4 0

_______________________________

Hey!!

Solution,

f^2-f-20

= f^2-(5-4)f-20

= f^2-5f+4f-20

= f(f-5)+4(f-5)

=(f-5)(f+4)

So the answer is (f-5)(f+4)

Hope it helps..

Good luck on your assignment

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Answer:

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Step-by-step explanation:

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3 years ago

3. Two dice are rolled. What’s the conditional probability that both dice are 5’s if it’s known that the sum of points is divisi

ArbitrLikvidat [17]

Answer:

$Pr =\frac{1}{3}$

Step-by-step explanation:

Given

$S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)$

$(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)$

$(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}$ --- sample space

First, list out all outcomes whose sum is divisible by 5

$A = \{(4,6), (5,5),(6,4)\}$

So, we have:

$n(A) = 3$

Next, list out all outcomes that has an outcome of 5 in both rolls

$B = \{(5,5)\}$

$n(B) =1$

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3 years ago

* The American Diabetes Association estimates that 8.3% of people in the

Leto [7]

Answer:

The probability that the diagnosis is correct is 0.95249.

Step-by-step explanation:

We are given that the American Diabetes Association estimates that 8.3% of people in the United States have diabetes.

Suppose that a medical lab has developed a simple diagnostic test for diabetes that is 98% accurate for people who have the disease and 95% accurate for people who do not have it.

Let the probability that people in the United States have diabetes = P(D) = 0.083.

So, the probability that people in the United States do not have diabetes = P(D') = 1 - P(D) = 1 - 0.083 = 0.917

Also, let A = event that the diagnostic test is accurate

So, the probability that a simple diagnostic test for diabetes is accurate for people who have the disease = P(A/D) = 0.98

And the probability that a simple diagnostic test for diabetes is accurate for people who do not have the disease = P(A/D') = 0.95

Now, the probability that the diagnosis is correct is given by;

Probability = P(D) $\times$ P(A/D) + P(D') $\times$ P(A/D')

= (0.083 $\times$ 0.98) + (0.917 $\times$ 0.95)

= 0.08134 + 0.87115

= 0.95249

Hence, the probability that the diagnosis is correct is 0.95249.

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3 years ago

Is the relation a function if the relation is not a function state why not

aivan3 [116]

Answer:

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3 years ago

The spinner shown has eight equal-sized sections. The pointer lands on an even number 135 times out of 250 spins. Select all the

denis23 [38]

Answer:

Only statements A and D are correct.

- The pointer lands on an even number more often than expected.

- The actual probability of landing on an odd number is 46%.

Step-by-step explanation:

The image of the spinner isn't shown, but the image obtained from this same question on as another brainly question has the spinner numbered from 1 to 8 inclusive, meaning that there's an equal number of even and odd numbers, 4 each. I cannot post the image as it will violate community guidelines on here and lead to question deletion.

The spinner lands on an even number 135 times out of 250 spins.

Let the probability of the spinner landing on an even number = P(E)

Let the probability that the spinner lands on an odd number = P(O)

The expected probability of landing on an even number = P(E) = (4/8) = 0.5

Similarly, the expected probability of landing on an odd number = P(O) = (4/8) = 0.5

So, examining the options one at a time.

A. The pointer lands on an even number more often than expected.

The expected probability of landing on an even number = P(E) = (4/8) = 0.5

In 250 trials, expected number of times the spinner should land on an even number = 0.5 × 250 = 125.

So, landing on an even number 135 times indicates that the pointer lands on an even number more often than expected (135 > 125)

This statement is correct.

B. The pointer lands on an even number less often than expected.

This is a direct contradiction to statement A, which we have proved to be correct, hence, statement B is not correct.

C. The expected probability of landing on an even number is 54%.

The expected probability of landing on an even number = P(E) = (4/8) = 0.5 = 50%

This statement is not correct.

D. The actual probability of landing on an odd number is 46%.

The actual probability of landing on an odd number = 1 - (135/250) (since odd and even are the only 2 sample spaces)

The actual probability of landing on an odd number = 1 - 0.54 = 0.46 = 46%

This statement is correct.

E. It is equally likely that the pointer will land on an even or odd number.

The expected probabilities are the same and points to an equal likelihood of the pointer landing an even or odd number, but, the actual probabilities (54% for an even number and 46% for an odd number), show that it is not equally likely that the pointer will land on an even or odd number.

Hence, this statement is not correct.

Hope this Helps!!!

8 0

3 years ago

Factorise f²-f-20 step by step ​

Factorise f²-f-20 step by step