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fgiga [73]
3 years ago
13

A completely reversible heat pump has a COP of 1.6 and a sink temperature of 300 K. Calculate (a) the temperature of the source

and (b) the rate of heat transfer to the sink when 1.5 kW of power is supplied to this heat pump.
Chemistry
1 answer:
sesenic [268]3 years ago
5 0

Answer:

(A) 800 K (B) 2.4 KW

Explanation:

We have given the COP =1.6

The sink temperature T_L=300K

We have to find the source temperature, that is T_H

(A) We know that COP of the heat pump is given by COP=\frac{T_H}{T_H-T_L}

So 1.6=\frac{T_H}{T_H-300}

1.6T_H-480=T_H

0.6T_H=480

T_H=800K

(B) We have given the work done =1.5 KW

The rate of heat transfer is given by Q_H=COP\times W=1.6\times 1.5=2.4KW

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