A completely reversible heat pump has a COP of 1.6 and a sink temperature of 300 K. Calculate (a) the temperature of the source

Question

3 years ago

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and (b) the rate of heat transfer to the sink when 1.5 kW of power is supplied to this heat pump.

1 answer:

sesenic [268] · Answer 1 · 2021-12-09T17:34:37+03:00

5 0

Answer:

(A) 800 K (B) 2.4 KW

Explanation:

We have given the COP =1.6

The sink temperature $T_L=300K$

We have to find the source temperature, that is $T_H$

(A) We know that COP of the heat pump is given by $COP=\frac{T_H}{T_H-T_L}$

So $1.6=\frac{T_H}{T_H-300}$

$1.6T_H-480=T_H$

$0.6T_H=480$

$T_H=800K$

(B) We have given the work done =1.5 KW

The rate of heat transfer is given by $Q_H=COP\times W=1.6\times 1.5=2.4KW$