According to the properties you provided, that should be metals.
Answer:
v = 20 m/s
Explanation:
Given that :
Initial Velocity of cars (u) = 0
Car with smaller mass = m
Car with larger mass = 2m
Final velocity of smaller mass = v
Final velocity of larger mass v2 = 10
Using the relation :
Initial momentum = final momentum
m1u1 + m2u2 = m1v1 + m2v2
Since u = 0
m1v1 + m2v2 = 0
mv + 2m * 10 = 0
mv + 20m = 0
mv = 20m
v = 20m / m
v = 20
Final velocity of larger mass car will be 20 m/s
Answer:
T = mg - (m²g/(I/R² + m))
Explanation:
Let T be the tension in the cable between the drum and the bucket
Now, by applying newton's second law of gravity on the downward movement of the bucket, we will obtain;
mg - T = ma - - - - (eq1)
Now, on the drum , a torque of TR will be acting which will create an angular acceleration of "α" in it.
Where R is the radius.
Let "I" denote the moment of inertia of the drum. Thus, we have;
TR = Iα
Now, the angular acceleration is expressed in the form;
α = a/R
Where a is the linear downward acceleration.
Thus;
TR = Ia/ R
T = Ia/ R²
Let's put Ia/ R² for T into equation 1 to give;
mg - Ia/R² = ma
Ia/R² + ma = mg
a( I/R² + m) = mg
a = mg/(I/R² +m)
Now putting mg/(I/R² +m) for a in eq 1 gives;
mg - T = m(mg/(I/R² +m))
T = mg - m(mg/(I/R² +m))
T = mg - m²g/(I/R² + m)
Answer:
ion is an electrically charged particle
Explanation:
there are 2 types of ions. anion an cation anion is negatively charged
cation is positively charged
<h3>Answer</h3>
option B)
19N
<h3>Explanation</h3>
If the object is at equilibrium, then the net force acting upon the object should be 0 N. Thus, if all the forces are added together, horizontal and vertical forces separately, then the resultant force (the vector sum) should be 0 Newton.
As we only need to find the magnitude of x-component of force F
so find all x component/horizontal forces acting on the object.
50cos(40) - 40cos(25) + 30cos(55) + x = 0
38.30 - 36.25 + 17.21 + x + = 0
19.26 + x = 0
x = - 19.26
x ≈ 19 (magnitude only)