Answer:
Area of the plates of a capacitor, A = 0.208 m²
Explanation:
It is given that,
Charge on the parallel plate capacitor, 
Electric field, E = 3.1 kV/mm = 3100000 V/m
The electric field of a parallel plates capacitor is given by :
A = 0.208 m²
So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.
see
below
Explanation:
refractive index = speed of light in vacuum / speed of light in medium
light travels at a speed of 3.0 x 10^8 m/s in vacuum
refractive index = 3.0 x 10^8 / 2.0 x 10^8
refractive index = 1.5
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The formula used in calculations relating to transformers
is:
<span>Secondary voltage
(Vs)/ Primary voItage (VP) = Secondary turns (nS)/
Primary turns (nP)</span>
Substituting the
given values to find for Vs,
Vs / 120 V = 400
turns / 100 turns
<span>Vs = 480 V</span>
Explanation:
★A compound pendulum has an extended mass, like a swinging bar, and is free to oscillate about a horizontal axis. A special reversible compound pendulum called Kater’s pendulum is designed to measure the value of g, the acceleration of gravity.
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The time interval in which the larger force act is 1.1 seconds.
<h3>What is impulse?</h3>
The impulse produced by an object is determined from the product of force and time of force of the object.
The impulse experienced by an object is the product of mass and velocity of the object or simply the impulse experienced by object is equal to change in the momentum of an object.
J = Ft
where;
- F is the applied force
- t is the time of force acting
The magnitude of the force that produce impulse of 3 Ns for 3.2 seconds is calculated as;
F = J/t
F = (3 Ns) / (3.2 s)
F = 0.94 N
The magnitude of the force that is three times larger is calculated as;
F₂ = 3 x 0.94 N
F₂ = 2.82 N
The time interval of the larger force is calculated as;
t₂ = J/F₂
t₂ = 3 / 2.82
t₂ = 1.1 seconds
Thus, the impulse experienced by an object is a function of force and time of force action.
Learn more about impulse here: brainly.com/question/25700778
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