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Harlamova29_29 [7]
3 years ago
12

Benjamin, a transport technician, was punched by a patient in the

Physics
1 answer:
Masja [62]3 years ago
6 0
Yes....................
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If you were on a ship at sea, and a tsunami passed under your ship, what would probably be your reaction? explain.
swat32
<span>Extremely powerful single waves have no effect on ships at sea since the depth of water allows the energy to be distributed over hundreds and thousands of feet. In deep water, the bigger the wave, the faster it moves and the slower the surface changes height. As the wave gets into shallow waters, it slows down and can start to pile up to large heights.</span>
6 0
3 years ago
You throw a baseball at an angle of 30.0∘∘ above the horizontal. It reaches the highest point of its trajectory 1.05 ss later. A
garri49 [273]

Answer:

The speed with which the baseball leaves the hand = 20.58 m/s

Explanation:

The time take to reach highest height during a projectile's flight is given by

t = (u sin θ)/g

u = initial velocity of the baseball = ?

θ = angle of throw above the horizontal

g = acceleration due to gravity = 9.8 m/s²

1.05 = (u sin 30)/9.8

u = (1.05 × 9.8)/0.5

u = 20.58 m/s

7 0
3 years ago
If I were to transmit a radio wave in our three dimensional world could a fourth dimensional “being” be able to receive it?
Morgarella [4.7K]
Depends. Are you talking about a mathematical 4th dimension (in which there is infinite dimensions) or some sort of etheral dimension (in which there is no scientific evidence for)

If you mean the first then yes. But it depends how these beings exist. From our understanding we only can theorize shapes in 4-d and if we assume that there is only one universe these "beings" arleady exist and thus any message in 3-d would be sent to them like a shadow ("flat").
If they exist in a alternate "plane" then you would need some method to transverse this plan and if u did, then we would easily be able to communicate, but we would at first sound like a wild animal. They either would ignore us, not understand or perceive us, or they would attempt to send back a signal (essential they are ET's)

IF you mean the second then thats some mystic stuff and its pretty creepy (although a fun read for me :P)
 
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5 0
3 years ago
A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res
Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy E_k = \frac{mv^2}{2} where m is bullet mass, v is the velocity

Formula for work W = FS where F is the average force and S is the distance travelled.

E_k = W

\frac{mv^2}{2} = FS

F = \frac{mv^2}{2S}

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

F = \frac{0.0042*370^2}{2*1.2} = 239.575 N

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)

We also have v(t) = v_0 + at

At the time the bullet is coming to rest, v(t) = 0, a = -57041.67 m/s^2

Therefore, 0 = 370 - 57041.67t

t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms

3 0
4 years ago
How much kinetic energy does a 6kg cart have when moving at 4 m/s?
Arturiano [62]

Given:

mass = 6 kg

velocity = 4 m/s

To find:

Kinetic energy of the cart = ?

Formula used:

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Solution:

Kinetic energy of the moving cart is given by,

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Kinetic energy =\frac{1}{2} \times 6 \times \ 4 \times 4

Kinetic energy = 48 Joule

Thus, the kinetic energy of the moving cart is 48 Joule.

3 0
4 years ago
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