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Harlamova29_29 [7]
2 years ago
12

Benjamin, a transport technician, was punched by a patient in the

Physics
1 answer:
Masja [62]2 years ago
6 0
Yes....................
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What are two reasons why a home computer scanner requires
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Answer: C and D

Explanation: a p e x

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When the distance between two objects doubles, what happens to the gravitational attraction between these two objects?
Feliz [49]

Answer:

As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.  

The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.  

At that point by Newton's All inclusive Law of Attractive energy;  

F=GMm/R^2  

Mm= result of the majority  

R=Distance Between the two masses by focus.  

On the off chance that R is multiplied, new force=GMm/(2R)^2  

=GMm/4R^2  

Unique Power/New Force=4/1  

F/4=New Power

8 0
3 years ago
31. If you threw a baseball straight out at 45 m/s from a height of 1.5 meters (A) how long would it be in the air? B) How far o
coldgirl [10]

Answer:

A) t = 0.55 s

B) x = 24.8 m

Explanation:

A) We can find the time at which the ball will be in the air using the following equation:

y_{f} = y_{0} + v_{0y}t - \frac{1}{2}gt^{2}    

Where:

y_{f} is the final height= 0  

y_{0} is the initial height= 1.5 m

v_{0y} is the component of the initial speed in the vertical direction = 0 m/s        

t: is the time =?      

g: is the gravity = 9.81 m/s²

0 = 1.5 m - \frac{1}{2}9.81 m/s^{2}t^{2}

By solving the above equation for t we have:

t = \sqrt{\frac{2*1.5 m}{9.81 m/s^{2}}} = 0.55 s  

Hence, the ball will stay 0.55 seconds in the air.

                             

B) We can find the distance traveled by the ball as follows:

x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}

Where:  

a: is the acceleration in the horizontal direction = 0  

x_{f} is the final position =?  

x_{0} is the initial position = 0      

v_{0x} is the component of the initial speed in the horizontal direction = 45 m/s                                                                                            

x_{f} = x_{0} + v_{0x}t + \frac{1}{2}at^{2}

x_{f} = 0 + 45 m/s*0.55 s + 0 = 24.8 m

Therefore, the ball will travel 24.8 meters.

I hope it helps you!

3 0
2 years ago
Which of the following are not examples of circular motion? Check all that<br> apply
CaHeK987 [17]

B.riding on a ferris wheel

E.a satellite orbiting the Earth

Explanation:

A person riding on a ferris wheel and a satellite orbiting the earth both depicts circular motion.

Circular motion is the motion of a body about a fixed axis or center.

  • The motion path of the body forms a circle around the center.
  • In circular motion, the travel path is along a circle.
  • An orbiting satellite traces out its orbit round the earth.
  • At certain times, it passes through that point over and over again.
  • This is similar to that of a ferris wheel

Other options gives other types of motion.

learn more:

circular motion brainly.com/question/2562955

#learnwithBrainly

5 0
3 years ago
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