Question

Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smaller sphere. If the electric field just outside of the smaller sphere is E0, then the electric field just outside of the larger sphere is

Answer 1

Answer:

1/9 E0

Explanation:

The computation is shown below:

As we know that

$E_0 = K \frac{Q}{r2}$

where,

E = Electric field strength

k = Coulomb's constant

Q = charge on the sphere

r = distance from the center of the sphere

It is given that

The radius of the larger sphere is three times larger than that of the smaller sphere i.e

$R'=3R$

$E'=k\frac{Q}{R'^2}$

$=k\frac{Q}{(3R)^2}$

$=\frac{1}{9}(k\frac{Q}{R^2})$

$=\frac{E_0}{9}$

hence, the last option is correct