The answer would be : A parallelogram with congruent sides does NOT guarantee that a quadrilateral is a rectangle
Just divide 18 by 20 , so its 0.9
Answer:
90
Step-by-step explanation:
it is 90 because in the first slot there can be any 10 numbers and in the second slot the set can contain any of the remaining 9 numbers and then we can multiply these two numbers together to find the total amount of sets.
hope this helps :)
Answer:
The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.
Step-by-step explanation:
We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.
If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.
The standard deviation of the sample is equal to:

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

35+55+a=180
90+x=180
-90. -90
A= 90