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ANEK [815]
3 years ago
5

A point charge (5.0 pC) is located at the center of a spherical surface (radius = 2.0 cm), and a charge of 3.0 pC is spread unif

ormly upon this surface. Determine the magnitude of the electric field 1.0 cm from the point charge.
Physics
1 answer:
Alla [95]3 years ago
8 0

Answer:

E = 0.45 kN/C

Explanation:

From; the question, we can opine that the electric field inside the hollow sphere as a result of the  charge at the surface is zero.

Using the equation:

\mathbf{E = kq/r^2}  to determine the magnitude of the electric field with the radius 1.0 cm from the point charge.

where ;

constant k = 8.98*10^9

point charge  q = 5.0 pC = 5.0 × 10⁻¹²; we have :

\mathbf{E = kq/r^2}

\mathbf{E =\dfrac{8.98*10^9*5*10^{-12}}{1.0^2}}

E = 0.45 kN/C

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In the image  attached with this answer are shown the given options from which only one is correct.

The correct expression is:

m \frac{d}{dt}v_{(t)}

Because, if we derive velocity v_{t} with respect to time t we will have acceleration a, hence:

m \frac{d}{dt}v_{(t)}=m.a

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m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{4}} and C is a constant

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m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{2}} and C is a constant

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