Answer:
C 3.33 Ω
Explanation:
From the equation given 1 / Rtot = 1/10 + 1/5 = 3/10
then Rtot = 10/3 = 3.33 Ω
As an aside:
When there are only two resistors in parallel, the equivalent R is
= R1*R2 / (R1 + R2) = 10*5 / (10+5) = 50 / 15 = 3.33 Ω
Answer:

Explanation:
here we know that car starts from rest and continue to accelerate till it will reach to maximum speed of 20 m/s
so we will have



so car will accelerate till t = 10 then it will move with uniform speed
so the distance moved by the car till it accelerates is given as



now it will move with uniform speed for next 36 s
so we have

so total distance moved by the car is given as



Answer:
The weight of the block on the moon is 15 kg.
Explanation:
It is given that,
The acceleration of the block, a = 7.5 m/s²
Force applied to the box, F = 70 N
The mass of the block will be, 

m = 9.34 kg
The block and table are set up on the moon. The acceleration due to gravity at the surface of the moon is 1.62 m/s². The mass of the object remains the same. It weight W is given by :


W = 15.13 N
or
W = 15 N
So, the weight of the block on the moon is 15 kg. Hence, this is the required solution.
Looks like you simply substitute the length of the femur