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3 years ago

A wire runs left to right and carries a current in the direction shown. What is the direction of the magnetic field at point Z?

Physics

2 answers:

Nezavi [6.7K]3 years ago

7 0

Answer:

D) Out of the screen

Explanation:

Vanyuwa [196]3 years ago

5 0

The correct option is out of the screen.

As the motion of positive charge is the direction of current in the wire. From the right-hand curl rule, the magnetic field direction will be outside the paper or the screen. As the <span>wire runs left to right and carries a current in the direction from left to right, the magnetic field lines will be outside the screen.</span>

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Explanation:

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3 years ago

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3 years ago

f a single circular loop of wire carries a current of 45 A and produces a magnetic field at its center with a magnitude of 1.50

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Answer:

Radius of the loop is 0.18 m or 18 cm

Explanation:

Given :

Current flowing through the wire, I = 45 A

Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T

Number of turns in circular wire, N = 1

Consider R be the radius of the circular wire.

The magnetic field at the center of the current carrying circular wire is determine by the relation:

$B=\frac{N\mu_{0} I}{2R}$

Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.

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3 years ago

Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular

RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, $\omega _i$ = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

$\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad$

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

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3 years ago

An object on a planet has a mass of 243 kg. What is the acceleration of the

Vesna [10]

Answer:

The gravitational acceleration of a planet of mass M and radius R

a = G*M/R^2.

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G = 6.67 x 10^-11 N (m/kg)^2

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3 years ago