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stiks02 [169]
3 years ago
9

135 apples are to be packed into boxes.each box can take only 12 apples.find the number of boxes that will be fully packed and t

he number of boxes that will remain.
Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0

Our total amount of apples is 135 apples, and the amount that each box can hold is 12.

So, that means we can make an equation for this.

The equation would be 135 = 12x.

Then, to find x we can divide both sides by 12.

135/12 = 11.25

Next, we take 11 and multiply it by 12 to see how many apples it is.

11 x 12 = 132

So, 135-132 equals 3.

3 is 1/4 of 12.

That means 11 boxes will be fully packed and 1/4 of a box will be filled.

jeka943 years ago
3 0

Answer:

11 boxes will be fully packed and .25 will be remaining

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Answer:

<h2>1529.4 m³</h2>

Step-by-step explanation:

Volume of a pyramid can be found by using the formula

v =  \frac{1}{3}  \times a \times h \\

a is the area of the base

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Since the base is a square we have

v =  \frac{1}{3}  \times  {15.3}^{2}  \times 19.6 \\  = 78.03 \times 19.6 \\  = 1529.388

We have the final answer as

<h3>1529.4 m³</h3>

Hope this helps you

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The table below shows the hourly temperatures, for a city in Ohio on February 10, 2012, as predicted by the weatherman at the lo
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See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.

b) In matrix form this is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)

c) The determinant is

\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16

d) Find three determinants:

\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608

\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368

\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304

So,

x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19

e) If the store doubled all prices and inventory, then the new matrix is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)

7 0
3 years ago
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