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Leona [35]
3 years ago
7

Consider water flowing through a cylindrical pipe with a variable cross-section. The velocity is v at a point where the pipe dia

meter is 1.0 cm. At a point where the pipe diameter is three times larger, the velocity is:
nine times larger than the initial velocity
one ninth the initial velocity
three times larger than the initial velocity
the same as the initial velocity
one third the initial velocity
Physics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

one ninth

Explanation:

d = 1 cm , v = v

D = 3d, V = ?

By the equation of continuity,

A V = a v

3.14 x D^2 / 4 x V = 3.14 x d^2 / 4 x v

9d^2 x V = d^2 x v

V = v / 9

Thus, the velocity becomes one ninth the initial velocity

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Softa [21]
<h2>Answer:</h2>

<u>Turning a magnet very quickly would be BEST used to create an electric current</u>

<h2>Explanation:</h2>

In Electromagnetic waves electric field produces magnetic field and vice versa. A moving magnet can produce electric current. Dynamo is the best example for it. In dynamo armature is rotated between the magnets which results in the development of electric field and hence an electric current is produced in it.

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Which of the following equations describes photosynthesis?​
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Explanation:

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2 years ago
5. What is the density of 4.5 mL of a liquid that has a mass of 1.3 grams?
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Answer:

A. 0.289g/mL

Explanation:

Using the equation for density which is d = m/v  or density = mass/volume, we input 1.3g/4.5mL and get 0.289g/mL.

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3 years ago
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On a highway curve with a radius of 46 meters, the maximum force of static friction that can act on a 1,200 kg car going around
Mekhanik [1.2K]

Answer:

v\approx 16.956\,\frac{m}{s}

Explanation:

The motion of the vehicule on a highway curve can be modelled by the following equation of equilibrium:

\Sigma F = f = m\cdot \frac{v^{2}}{R}

The maximum speed is:

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7 0
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Choose all facts that increase the orbital velocity of a vessel around planet B. Bigger mass of planet B smaller mass of planet
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Answer:

- Bigger mass of planet B  

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where

G is the gravitational constant

m is the mass of the vessel

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v is the orbital velocity of the vessel

Re-arranging the formula, we find an expression for v:

v=\sqrt{\frac{GM}{r}}

We see that:

- the bigger the mass of the planet, M, the bigger the velocity

- the bigger the distance between the vessel and the planet, r, the smaller the velocity

So, the correct choices that increase the orbital velocity are:

- Bigger mass of planet B  

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