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Leona [35]
3 years ago
7

Consider water flowing through a cylindrical pipe with a variable cross-section. The velocity is v at a point where the pipe dia

meter is 1.0 cm. At a point where the pipe diameter is three times larger, the velocity is:
nine times larger than the initial velocity
one ninth the initial velocity
three times larger than the initial velocity
the same as the initial velocity
one third the initial velocity
Physics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

one ninth

Explanation:

d = 1 cm , v = v

D = 3d, V = ?

By the equation of continuity,

A V = a v

3.14 x D^2 / 4 x V = 3.14 x d^2 / 4 x v

9d^2 x V = d^2 x v

V = v / 9

Thus, the velocity becomes one ninth the initial velocity

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According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

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F \alpha \frac{1}{d^{2}}    .... (1)

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As the distance between two charges increases by factor of three, let the new force be F'.

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Divide equation (2) by equation (1), we get

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