5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
infinite solutions
Step-by-step explanation:
Eliminate parentheses and collect terms:
3x -12 +5 -x = 2x -7
2x -7 = 2x -7
This is true for any value of x. There are an infinite number of solutions.
Answer:
y=2x-2
Step-by-step explanation:
Slope intercept form = y=mx+b
Where m=slope and b= y intercept
Reminder: the y intercept is where x=0
Looking at the graph, the y intercept is given as (0,-2)
There are also two points given (0, -2) and (2,2)
Reminder: to find the slope, divide the changes in y by the changes in x or substitute the numbers into this equation: y2-y1/x2-x1
2-(-2)/2-0=4/2
m=2
Now that we have the slope and y intercept, sbstitute into the equation y=mx+b:
y=2x-2
Answer:
a = 1
b = -1
c = -2
Step-by-step explanation:
We reorder the equation in such way that let us see the usual
ax² + bx + c = 0
Then the original quation is:
-2 = - x + x² - 4 ⇒ 0 = 2 - x + x² - 4 ⇒ x² - x - 2 = 0
Now we are able by simply inspection to identify a, b . c comparing our equation with the general equation so :
a = 1
b = -1
c = -2
From 6,1 to 7,4
We can determine the slope of the line
rise/run
3/1=3
Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A
(-4,1) and (-2,7)
