Answer:
When you place an iron nail in a basin of water and leave it for two days, what will happen to the iron nail? It will form rust on the surface of the nail. Rust forms when iron combines with oxygen to form iron oxide.
Explanation:
Assuming they were clean of rust to begin with, and are made of an ordinary steel - they start to rust - will turn orange, and the orange sediment...
Not much if any while it's in the water for that period of time. However once you remove it then it will be exposed two oxygen and will start to ox...
If it is not coated properly It will form Rust .
Answer:
21.65
Explanation:
The average = total divided by the number of readings
21.57
22.04
<u>21.35</u>
Total = 64.96
Average = 64.96 / 3 = 21.65
Answer: 0.84 g
Explanation:

Given: moles of iron = 0.015
Molar mass of iron = 56 g/mol

Thus 0.84 g of iron participated in the chemical reaction.
Answer:-
95 grams
Explanation:-
Let the mass of water to be added be M
So total mass = 5 + M
So 5% of this solution has 5g of NaCl by mass.
∴ (M+5) x (5/100) = 5
M+5 = 5 x 100/5
M+5=100
M= 100-5
95
So amount of water to be added is 95 gram
Answer:The answer is I = 12 / 10 = 1.2 amperes.
Explanation: